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Chapter 23: Q. 28 (page 654)

An electron traveling parallel to a uniform electric field increases its speed from 2.0脳107m/sto4.0脳107m/s over a distance of 1.2cm. What is the electric field strength?

Short Answer

Expert verified

The electric field strength isE=2.8x105N/C

Step by step solution

01

Given information and formula used

Given :

The electron's speed ranges from : 2.0脳107m/sto4.0脳107m/s

Over a distance of : 1.2cm

Theory used :

Newton's Second law states :

F=m路aFE=qE鈬�qE=m路a

Formula for acceleration :vf2=vi2+2ad

02

Calculating the electric field strength 

Using the kinematics equation, we calculate acceleration :

vf2=vi2+2ad鈬�vf2-vi2=2ad鈬�a=vf2-vi22d=(4.0脳107)2-(2.0脳107)22x0.012=5脳1016m/s虏

We can now use Newton's Second Law. The force in this situation is the electric force, which is given by F=qE.

qE=ma鈬�E=maq=(9.1x10-31)脳(5脳1016)1.6x10-19鈬�E=2.8x105N/C

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