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A 12-cmlong thin rod has the nonuniform charge density λ(x)=(2.0nC/cm)e-|x|/(6.0cm), where localid="1648623923714" xis measured from the center of the rod. What is the total charge on the rod?

Hint: This exercise requires an integration. Think about how to handle the absolute value sign.

Short Answer

Expert verified

The total charge on the rod is Qis15.171nC.

Step by step solution

01

Values for calculation for total Charge on the rod 

To calculate the overall charge on an object,

The number of electrons applied is multiplied by the constant value ofe.

l=12cm→0.12m

The nonuniform charge density is calculated as follows:

λ(x)=(2.0nC/cm)e-|x|/(6.0cm)

02

Calculation for total charge interms of dQ

we have to integrate :

Q=∫dQ

Q=2∫0cm6cmλ(x)dx

Q=2∫0cm6cm(2.0nC/cm)e-x/(6.0cm)dx

Q=2(2.0nC/cm)∫0cm6cme-x/(6.0cm)dx

03

Calculation of total charge on the rod

Q=(-24.0nC)e-x/(6.0cm)0cm6.0cm

Q=(-24.0nC)e-1-e0

Q=(-24.0nC)(0.36787-1)

Q=(-24.0nC)(-0.63213)

Q=15.171nC

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