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Chapter 36: Q. 46 (page 1060)

Two events in reference frame S occur 10渭s apart at the same point in space. The distance between the two events is 2400min reference frame S'.

a. What is the time interval between the events in reference frame S鈥�?

b. What is the velocity ofS'relative to S?

Short Answer

Expert verified

a. The time interval between the events in the reference frame S'is 12.8渭s.

b. The velocity of S' relative to Sis0.480c.

Step by step solution

01

Part (a) Step 1: Given Information

We need to find the time interval between the events in reference frameS'.

02

Part (a) Step 2: Simplify

Consider :

鈭�x'=2400mt=10脳10-6s

We finding time interval between the events in reference frame S':

鈭�t2=c鈭�t2-鈭�x2=c鈭�t'2-鈭�x'2c鈭�t'2=(c脳10脳10-6)2+24002 c鈭�t'2=3.02脳106+2.42脳106c鈭�t'2=3.02+2.42脳106c鈭�t'2=3.841脳103鈭�t'=3.841脳1033脳108=12.8渭s

03

Part (b) Step 1: Given Information

We need to find the velocity of S'relative toS.

04

Part (b) Step 2: Simplify

The velocity of S'relative to S, as:

t'=纬t-谓xc2鈫�v=0.480c

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