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Chapter 36: Q. 2 (page 1059)

At t=1.0s, a firecracker explodes at x=10min reference frame S. Four seconds later, a second firecracker explodes at x=20m. Reference frame S鈥� moves in the x-direction at a speed of 5.0m/s. What are the positions and times of these two events in frame S鈥�?

Short Answer

Expert verified

Position of the events are 5mand-5m.

Times of the events are1sand5s.

Step by step solution

01

Given information

We have given,

First firecracker positon =10m

Second firecracker positon =20m

Velocity of frame =5m/s

We have to find the positon and time of the events in the S' frame.

02

Simplify

Using Galilean transformation,

x'=x-vt

where x' is coordinate in S' frame.

For first event in the S' frame

x'=x-vtx'=10m-5m/s脳1sx'=5m

Since,

t'=tt'=1s

For second event in the S' frame

x'=x-vtx'=20m-5m/s脳5sx'=-5m

Since,

t'=tt'=5s

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