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Chapter 34: Q. 12 (page 990)

II A costume jewelry pendant made of cubic zirconia is submerged in oil. A light ray strikes one face of the zirconia crystal at an angle of incidence of25掳. Once inside, what is the ray's angle with respect to the face of the crystal?

Short Answer

Expert verified

The ray's angle with respect to the face of the crystal is胃'=73.6掳

Step by step solution

01

Snell’s law of refraction:  

Snell's law:

n1sin鈦�胃1=n2sin鈦�胃2

Index of refraction is

n=cv


On the side with the higher index of refraction, the ray is closer to the normal.

When the angle of incidence is and total internal reflection(TIR)occurs.

02

Determine the ray's angle with respect to the face of the crystal:

n1=1.46is the index of refraction of oil.

n2=2.18is the index of refraction of Cubic Zirconia.

胃1=25掳is the angle of incidence of the light ray on the Cubic Zirconia.

03

Apply Snell's Law

Regroup snell's Law:

sin胃2=n1sin胃1n2

Solve胃2:

胃2=sin-1n1sin胃1n2

Substitute the values:

胃2=sin-1(1.46)sin25掳2.18

Simplify:

=16.44掳

04

Determine the value ofθ:

The angle of refraction胃2of the ray with respect to the face of the crystal is related to the angle of refraction localid="1649255318937" 胃':

胃'=90掳-胃2

Substitute the value oflocalid="1649255322452" 胃2:

localid="1649255325438" =90掳-16.44掳

Substract:

=73.6掳

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Most popular questions from this chapter

A fortune teller鈥檚 鈥渃rystal ball鈥� (actually just glass) is 10 cm in diameter. Her secret ring is placed 6.0 cm from the edge of the ball.

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