91Ó°ÊÓ

It connects the incident angle ${\mathrm{θ}}_1$to the refraction angle ${\mathrm{θ}}_2$, moreover because the incident medium's $n_1$and refracted medium's $n_2$indexes of refraction.

$n_1\sin {\mathrm{θ}}_1=n_2\sin {\mathrm{θ}}_2$

Angles of incidence and refraction are measured in regard to the conventional line where the ray intersects the two media's interface. Medium $2$is more optically thick (has a better refractive index) than medium $1$if the refracted ray is closer to the traditional than the incident ray. Within the same plane because the incident ray, the refracted ray, and also the normal line.

The angle of incidence of the beam is ${\mathrm{θ}}_1=37°$

${\mathrm{θ}}_2=26°$is that the laser beam's angle of refraction

The index of refraction of air is $n_1=1.00$

To obtain n2, rearrange Snell's law from equation.

$n_2=\frac{n_1\sin {\mathrm{θ}}_1}{\sin {\mathrm{θ}}_2}$

Put the values,

$n_2=\frac{(1.00)\left(\sin 37°\right)}{\sin 26°}$

$=1.37$