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Chapter 26: Q. 4 (page 737)

Figure EX26.4 is a graph of Ex. The potential at the origin is -50V. What is the potential at x=3.0m?

Short Answer

Expert verified

The required potential is-550V

Step by step solution

01

Given information and formula used 

Given :

The potential at the origin : -50V

To find : The potential at :x=3.0m

Graph -

Theory used :

Potential difference is :鈭�V=Vf-Vi=鈭�Ex路鈭�x

02

Calculating the required the potential difference  

Using the formula to calculate potential difference, we have :

鈭�V=Vf-Vi=鈭�Ex路鈭�x鈬�V3-V0=-鈭�02Ex路dx-鈭�23E路dx鈬�V3+50=-200脳2-鈭�23(600-200x)dx鈫�{fromgraph}鈬�V3=-400-50-[600x-200x虏2]23 =-450-(900-800)=-450-100=-550V

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Most popular questions from this chapter

A battery with an emf of 60Vis connected to the two capacitors shown in FIGURE P26.62. Afterward, the charge on capacitor 2is 450渭C. What is the capacitance of capacitor 2?

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