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Chapter 26: Q. 17 (page 738)

How much work does the charge escalator do to move 1.0渭C of charge from the negative terminal to the positive terminal of a 1.5V battery?

Short Answer

Expert verified

The work done is1.5渭J

Step by step solution

01

Given information and theory used  

Given :

Charge :1.0渭C

Battery Voltage : 1.5V

Theory used :

The work is equal toW=q鈭�V

02

Calculating Work done

The work is equal to the charge's change in potential energy, which is equal to the charge multiplied by the potential difference: W=q鈭�V

鈬�W=q鈭�V=1.0渭C路1.5V=1.5渭J

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Most popular questions from this chapter

The potential at the center of a 4.0-cm-diameter copper sphere is 500 V, relative to V = 0 V at infinity. How much excess charge is on the sphere?

a. Suppose that E鈫�=0鈫�V/mthroughout some region of space. Can you conclude that V=0Vin this region? Explain.

b. Suppose that V=0V throughout some region of space. Can you conclude that E鈫�=0鈫�V/m in this region? Explain.

The parallel-plate capacitor in Figure Q26.11 is connected to a battery having potential difference 鈭�Vbat. Without breaking any of the connections, insulating handles are used to increase the plate separation to 2d.

a. Does the potential difference 鈭�VCchange as the separation increases? If so, by what factor? If not, why not?

b. Does the capacitance change? If so, by what factor? If not, why not?

c. Does the capacitor charge Qchange? If so, by what factor? If not, why not?

Figure EX26.11 is a graph ofVversusx. Draw the corresponding graph ofExversusx.

An infinitely long cylinder of radius Rhas linear charge density I. The potential on the surface of the cylinder isV0, and the electric field outside the cylinder is localid="1648568519666" Er=位/2蟺鈭�0r. Find the potential relative to the surface at a point that is distance r from the axis, assuming localid="1648568540457" r>R.
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