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How much work does the charge escalator do to move 1.0μC of charge from the negative terminal to the positive terminal of a 1.5V battery?

Short Answer

Expert verified

The work done is1.5μJ

Step by step solution

01

Given information and theory used  

Given :

Charge :1.0μC

Battery Voltage : 1.5V

Theory used :

The work is equal toW=q∆V

02

Calculating Work done

The work is equal to the charge's change in potential energy, which is equal to the charge multiplied by the potential difference: W=q∆V

⇒W=q∆V=1.0μC·1.5V=1.5μJ

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