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Chapter 35: Q. 37 (page 1018)

You鈥檝e been asked to build a telescope from a 2.0xmagnifying lens and a 5.0xmagnifying lens.

a. What is the maximum magnification you can achieve?

b. Which lens should be used as the objective? Explain.

c. What will be the length of your telescope?

Short Answer

Expert verified

a. The maximum magnification isMmax=2.5.

b. The lens should be used as the objective isL鈮�fR=fL.

c. The length of the telescope isL=7.

Step by step solution

01

Part (a) Step 1: Given Information.

We need to find out the maximum magnification to achieve.

02

Part(a) Step 2 : Simplify

Maximum magnification:

Mmax=fobjfobjMmax=52Mmax=2.5.

03

Part (b) Step 1 : Given Information.

We need to find which lens should be used as the objective.

04

Part (b) Step 2: Explanation.

As we know that the distance between eyepiece and objective lenses are lightly less than to their focal length.

L鈮�fR+fL.

05

Part (c) Step 1 : Given Information.

We need to find the length of the telescope.

06

Part (c) Step 2: Calculation.

Length of telescope is:

L=fR+fLL=5+2L=7.

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Most popular questions from this chapter

White light is incident onto a 30掳prism at the 40掳angle shown in figurep35.41. violet light emerges perpendicular to the rear face of the prism. The index of refraction of violet light in this glass is 2.0%larger than the index of refraction of red light. At what angle does red light emerges from the rear face?

Infrared telescope, which use special infrared dictators, are able to do peer farther into star-forming regions of the galaxy because infrared light is not scattered as strongly as is visible light by the tenuous clouds of hydrogen gas from which new stars are created. for what wavelength of light is the scattering only 1%that of light with visible wavelength of 500nm?

The resolution of a digital cameras is limited by two factors diffraction by the lens, a limit of any optical system, and the fact that the sensor is divided into discrete pixels. consirer a typical point-and--shoot camera that has a 20-mm-focal-lengthlens and a sensor with 2.5-渭m-widepixels.

(a) . First, assume an ideal, diffractionless lens, at a distance of 100m,what is the smallest distance, in cmbetween two point sources of light that the camera can barely resolve? in answering this question, consider what has to happen on the sensor to show two image points rather than one you can use S1=fbecauses>>f.

(b) . You can achieve the pixel-limied resolution of part a only if the diffraction which of each image point no greater than the diffraction width of image point is no greater than 1pixel in diameter. for what lens diameter is the minimum spot size equal to the width of a pixel ? use 600nmfor the wavelength of light.

(c). what is the f-numberof the lens for the diameter you found in part b? your answer is a quite realistic value of the f-numberat which a camera transitions from being pixel limited to being diffraction limited for f-numbersmaller than this (larger-diameter apertures), the resolution is limited by the pixel size and does not change as you change the apertures. for f-numberlarger than this (smaller-diameter apertures). the resolution is limited by diffraction and it gets worse as you "stop down" to smaller apertures.

Two light bulbs are 1.0mapart. from, what distance can these light bulbs be marginally resolved by a small telescope with a 4.0-cm-diameterobjective lens? assume that the lens is diffraction limited and位=600nm.

A microscope has a 20cmtube length. What focal-length objective will give total magnification localid="1649845070556" 500脳when used with an eyepiece having a focal length 5.0cm?
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