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Chapter 35: Q. 2 (page 1016)

A converging lens with a focal length of 40cmand a diverging lens with a focal length of -40cmare 160cmapart. A 2cmtall object is 60cmin front of the converging lens.

a. Use ray tracing to find the position and height of the image. Do this accurately using a ruler or paper with a grid, then make measurements on your diagram.

b. Calculate the image position and height. Compare with your ray-tracing answers in part a.

Short Answer

Expert verified

a. The ray tracing to find the position and height of the image is given below.

b. The position of the image is120cmaway from the first lens.

Step by step solution

01

Part (a) 1:Given Information 

We need to find the position and height of the image using ray tracing.

02

Part (a) step 2:Simplify

Consider:

S1=60cmf8=40cm

03

Part (b) step 1: Given Information

We need to calculate the image position and height.

04

Part (b) step 2: Simplify

First, finding to S'1:

1S'1=1f8-1S11S'1=140cm-160cm1S'1=1120cmS'1=120cm

Now, finding the magnification of the first lens:

m1=S'1S1m1=-120cm60cm=-2

For the second lens S'2:

1S'2=1S2+1f21S'2=1+40cm+1-40cmS'2=-20cm

Next, magnification of the second lens :

m2=-S'2S2m2=--20cm40cm=+0.5

At last, total magnification of lens :

M=m1脳m2=-2脳0.5=-1

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