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Chapter 42: Q 29 Exercise (page 1236)

What is the energy (in MeV) released in the alpha decay ofPu239?

Short Answer

Expert verified

Therefore, the energy is5.2452765MeV

Step by step solution

01

Given information

mPu239=239.052157umU235=235.043924umHe4=4.002602u1u=931.5MeVc2

02

Explanation

The decay is given as:

Pu239鈫�U235+He4

We have the formula:

E=螖mc2鈫�(Equation 1.)

03

Calculation

Now, finding the value of

螖m=mPu239m-U235-mHe4螖m=(239.052157u)-(235.043924u)-(4.002602u)螖m=0.005631u

We will now find the energy:

E=螖mc2E=(0.005631u)c2脳931.5MeVc21uE=5.2452765MeV

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Most popular questions from this chapter

Particle accelerators fire protons at target nuclei so that investigators can study the nuclear reactions that occur. In one experiment, the proton needs to have 20 MeV of kinetic energy as it impacts a 207 Pb nucleus. With what initial kinetic energy (in MeV) must the proton be fired toward the lead target? Assume the nucleus stays at rest

A 115 mCi radioactive tracer is made in a nuclear reactor. When it is delivered to a hospital 16 hours later its activity is 95 mCi. The lowest usable level of activity is 10 mCi.

a. What is the tracer鈥檚 half-life?

b. For how long after delivery is the sample usable?

Use the graph of binding energy to estimate the total energy released if a nucleus with mass number 240 fissions into two nuclei with mass number 120.

The element gallium has two stable isotopes: 69 Ga with an atomic mass of 68.92 u and 71 Ga with an atomic mass of 70.92 u. A periodic table shows that the chemical atomic mass of gallium is 69.72 u. What is the percent abundance of 69 Ga?

What energy (in MeV) alpha particle has a de Broglie wavelength equal to the diameter of a 238 U nucleus?
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