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Chapter 42: Q 28 Exercise (page 1236)

An unstable nucleus undergoes alpha decay with the release

of 5.52 MeV of energy. The combined mass of the parent and

daughter nuclei is 452 u. What was the parent nucleus?

Short Answer

Expert verified

Therefore, the parentnucleus with mass of228uisTh228.

Step by step solution

01

Given information

K伪=5.52MeVmHe4=4.002602umX+mY=452u

02

Explanation

We use the formula:

K伪=螖mc2K伪=mX-mY-mHec25.52MeV=mX-mY-mHe5.52MeVc21u931.5MeVc2=mX-mY-mHe0.0059259u=mX-mY-mHemX-mY=0.0059259u+mHe4mX-mY=0.0059259u+4.002602umX-mY=4.0085279u

We got a system of two equations:

mX+mY=452umX-mY=4.0085279u

03

Calculations

We will find the value of mX:

2mX=452u+4.0085279u2mX=456.008529umX=456.008529u2鈬�mX=228.0042645u

So, nucleus with mass of228uisTh228.

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