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Chapter 7: Q. 25 (page 178)

The 100kgblock in FIGURE EX7.25takes 6.0sto reach the floor after being released from rest. What is the mass of the block on the left? The pulley is massless and frictionless.

Short Answer

Expert verified

The acceleration of the2.0kgblocks is2.16m/s2

Step by step solution

01

Given information 

Mass of right block, M=100kg

Time taken t=6s

Distance moveds=1m

02

Explanation

Equation of motion for mass m

T-mg=ma鈥�鈥�(1)

Equation of motion for mass M:

Mg-T=Ma鈰�鈰�(2)

On adding equation (1)and(2)

gM-m=aM+mm=Mg-ag+a

Acceleration a can be calculated as follows.

localid="1649613906426" s=ut+12at2u=0s=1mt=6s1m=0+12a6s2a=236m/s2a=0.055m/s2m=100kg9.8m/s2-0.055m/s29.8m/s2+0.055m/s2m=98.87kg

The mass of the block on the left side is98.87kg

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