/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 24 The 1.0 kg block in FIGURE EX7... [FREE SOLUTION] | 91Ó°ÊÓ

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The 1.0kgblock in FIGURE EX7.24is tied to the wall with a rope. It sits on top of the 2.0kgblock. The lower block is pulled to the right with a tension force of 20N. The coefficient of kinetic friction at both the lower and upper surfaces of the 2.0kgblock is μk=0.40

a. What is the tension in the rope attached to the wall?

b. What is the acceleration of the 2.0kgblock?

Short Answer

Expert verified

(a) The tension in the rope attached to the wall is 3.92N

(b) The acceleration of the2kgblock.

Step by step solution

01

Given information (part a)

Mass of lower block, M=2kg

Mass of the upper block, m=1kg

External force Fext=20N

Coefficient of kinetic frictionμk=0.4

02

Explanation (part a)

The tension in the rope will be equal to frictional force acting on 1 kg mass.

T=μkmgm=1kgg=9.8m/s2T=0.41kg9.8m/s2=3.92N

The tension in the rope is3.92N

03

Given information (part b)

Mass of lower block,M=2kg

Mass of the upper block,m=1kg

External forceFext=20N

Coefficient of kinetic frictionμk=0.4

04

Explanation (part b)

Frictional force at the upper and lower surface of 2 kg block will try to prevent its motion.

The equation of motion of 2 kg block is as follows.

Ma=Fa-T-fkwherefk=μkm+MgMa=Fa-T-μkm+Mg2kga=20N-3.92N-0.41kg+2kg9.8m/s22kga=4.32Na=4.32N2kga=2.16m/s2

The acceleration of the 2kgblock is 2.16m/s2

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