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What is the force of attraction between a 50kgwoman and a 70kgman sitting 1.0mapart?

Short Answer

Expert verified

The force of attraction between the man and woman is2.3310-7N.

Step by step solution

01

Given information.

Mass of man (m1) = 70kg, mass of woman (m2) = 50kg, distance between them (r) = 1m.

02

Calculation.

We know, gravitational force is given by : F=Gm1m2r2.

Therefore, the gravitational force of attraction between the man and woman is :

F=Gm1m2r2.=6.6710-11Nm2/kg2(50kg)(70kg)(1.0m)2.=2.3310-7N.

03

Final answer.

The gravitational force between the man and woman is2.3310-7N.

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