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Saturn’s moon Titan has a mass of 1.35*1023kgand a radius of2580km. What is the free-fall acceleration on Titan?

Short Answer

Expert verified

The free-fall acceleration on Titan is 1.35m/s2.

Step by step solution

01

Given information.

Mass of Titan = 1.35*1023kg,radius of Titan = 2580km.

02

Calculation.

The formula for free-fall acceleration is given by : g=GMR2.

Here G,MandRare universal gravitational constant, mass of titan and radius of titan respectively.

Calculation:

Now substitute this values to the equation to calculate g :

localid="1648481878598" g=(6.67×10-11N·m2/kg2)(1.33×1023kg)(2580×103m)2=1.35m/s2.

03

Final answer.

The free-fall acceleration on Titan is1.35m/s2.

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