91Ó°ÊÓ

The initial velocity of a car is $v_{is}=0mph$.

The final velocity of a car is role="math" localid="1648060853938" $v_{fs}=60mph$.

Time role="math" localid="1648061198818" $∆t=10s$

As we need to find the answer in SI units, convert velocity in mph to $\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$.

$1mph=0.447\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$

$v_{fs}=60×0.447=26.82\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$

Use kinematical equation, $v_{fs}=v_{is}+a∆t$

Substitute the known values,

$$\begin{gathered} 26.82=0+a\left(10\right) \\ a=\frac{26.82}{10} \\ =2.68 \\ ≈2.7\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right. \end{gathered}$$

Therefore, the constant acceleration of a car in SI units is$2.7\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right.$.

Use kinematical equation, ${v^2}_{fs}={v^2}_{is}+2a_s∆s$.

Substitute the known values,

localid="1648061677839" $$\begin{gathered} 26.{82}^2=0+2\left(2.7\right)∆s \\ 719.31=5.4∆s \\ ∆s=\frac{719.31}{5.4} \\ ≈133m \end{gathered}$$

Convert the obtained answer in SI units to feet.

localid="1648062335788" $1m=3.28ft$

localid="1648062347256" $$\begin{gathered} 133m=133×3.28 \\ ≈436ft \end{gathered}$$

Therefore, the distance traveled by car in SI units is $133m$and in feet is

436 ft. .