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Chapter 2: Q. 1 (page 59)

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 50 mph. Beth leaves Los Angeles at 9:00 a.m. and drives a steady 60 mph. a. Who gets to San Francisco first? b. How long does the first to arrive have to wait for the second?

Short Answer

Expert verified

(a) Person B will first rich Place S.

(b) Person B will wait for 20 minutes for Person A to arrive.

Step by step solution

01

Given information

The velocity of person A vA=50mph

The velocity of person B vB=60mph

Distance to place S x=400mi

02

Part (a)Time required for person A to reach place S.

Person A is moving with velocity50mph.

The time required for person A to cover 400 miles is

localid="1647961767711" tA=xvAtA=40050tA=8hours

Person A takes 8hoursto reach the place S.

A person A will reach place S at 8hoursfrom 8:00am, that is, at 4:00pm.

03

Time required for Person B to reach Place S.

Person B is moving with velocity 60mph.

The time required for Person B to cover 400 miles is

localid="1647962584022" tB=xvBtB=40060tB=203hours=6hours40minutes

Person B takes localid="1647962614155" 6hours40minutesto reach Place S.

A Person A will reach Place S at 6hours40minutesfrom 9:00am, that is, at 3:40pm.

Therefore, Person B will first reach place S.

04

Part (b)

Person A will reach Place S at 4:00pmand Person B will reach place S at 3:40pm.

A person A has to wait for Person B for

localid="1648451136316" 4:00pm-3:40pm=20minutes

Therefore, Person B has to wait for 20 minutes for person A.

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