/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 38 A block is suspended from a spri... [FREE SOLUTION] | 91影视

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Chapter 2: Q. 38 (page 61)

A block is suspended from a spring, pulled down, and released. The block鈥檚 position-versus-time graph is shown in FIGURE P2.38. a. At what times is the velocity zero? At what times is the velocity most positive? Most negative? b. Draw a reasonable velocity-versus-time graph.

Short Answer

Expert verified

Part (a)

The velocity is zero at t=0s,1s,2s,...

The velocity is most positive att=0.5s,2.5s,...

The velocity is most negative at t=1.5s,3.5s,...

Part (b)

The velocity-time graph is

Step by step solution

01

Given information

The position versus time graph of a block is shown as

02

Part (a)

The velocity is zero when the slope of the position-time graph is zero, it is most positive when the slope is most positive and is most negative when the slope is most negative.

The slope is zero at t=0s,1s,2s,...

The slope is most positive at t=0.5s,2.5s,...

The slope is most negative att=1.5s,3.5s,...

03

Draw velocity-versus-time graph.

With the help of the information in step 2, the velocity-versus-time graph is drawn as below

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