/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.10 A 20 kg child is on a swing that... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Q.10 (page 256)

A 20 kg child is on a swing that hangs from 3.0-m-long chains. What is her maximum speed if she swings out to a 45掳 angle?

Short Answer

Expert verified

As a result, the child's maximum speed is4.15m/s.

Step by step solution

01

Introduction

The distance travelled by an object per unit time is known as its speed.

02

Explanation

Draw the child's and swing's free body diagrams.

Calculate the child's increased height.

Putting 3mfor ll, 0.7071for cos45掳in equation x=lcos45掳

x=(3m)(0.7071)

=2.12m

Putting 2.12mfor x, and 3mfor lin equation h=l-x

h=3m-2.12m

=0.88m

Calculate the child's maximum speed.

At the two positions depicted in the diagram, apply the law of conservation of energy.

KEi+PEi=KEf+PEf

12mvmax2+0=0+mgh

vmax=2gh

Putting 9.81m/s2for g, and 0.88mfor hby equation.

vmax=29.81m/s2(0.88m)

=17.26m2/s2

=4.15m/s

As a result, the child's maximum speed is 4.15m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A roller-coaster car rolls down a frictionless track, reaching speed v0 at the bottom. If you want the car to go twice as fast at the bottom, by what factor must you increase the height of the track? Explain.

FIGUREEX10.28shows the potential energy of a 500gparticle as it moves along the x-axis. Suppose the particle鈥檚 mechanical energy is 12J.

a. Where are the particle鈥檚 turning points?

b. What is the particle鈥檚 speed when it is at x=4.0m?

c. What is the particle鈥檚 maximum speed? At what position or positions does this occur?

d. Suppose the particle鈥檚 energy is lowered to 4.0J. Can the particle ever be at x=2.0m? Atx=4.0m?

A system in which only one particle can move has the potential energy shown in FIGUREEX10.31. What is the y-component of the force on the particle at y=0.5mand 4m?

A sled starts from rest at the top of the frictionless, hemispherical, snow-covered hill shown in FIGURE CP10.74.

a. Find an expression for the sled鈥檚 speed when it is at angle 蠒.

b. Use Newton鈥檚 laws to find the maximum speed the sled can have at angle 蠒without leaving the surface.

c. At what angle 蠒maxdoes the sled 鈥渇ly off鈥� the hill?

A 10 kg runaway grocery cart runs into a spring with spring constant 250 N/m and compresses it by 60 cm. What was the speed of the cart just before it hit the spring?
See all solutions

Recommended explanations on Physics Textbooks

Particle Model of Matter

Read Explanation

Physical Quantities And Units

Read Explanation

Solid State Physics

Read Explanation

Rotational Dynamics

Read Explanation

Energy Physics

Read Explanation

Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.