/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.40 A cable with 20.0聽N of tension ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Q.40 (page 257)

A cable with 20.0N of tension pulls straight up on a 1.50kg block that is initially at rest. What is the block鈥檚 speed after being lifted 2.00m? Solve this problem using work and energy.

Short Answer

Expert verified

The block's speed =7.302m/s.

Step by step solution

01

Speed : 

It is the change in an object's location with regard to time.

02

Explanation : 

Rope's tension T=20N

block's massm=1.5kg

lift of h = 2m

Work done is,

W=T脳h

Block's kinetic energy is calculated by,

KE=12mv2

KE= kinetic energy

m= block's mass

v= block's velocity

To lift the block upto 2m, the work required is,

W=T脳hW=20脳2=40J

Since the work is done to increase the block's potential energy, the change in potential energy equals the change in kinetic energy, according to the law of energy conservation.

KE=W

Block's velocity after being lifted for h=2mis,

12mv2=KE=W12脳1.5脳v2=40v=7.302m/s

Hence, block's velocity is7.302m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sam, whose mass is 75kg, straps on his skis and starts down a 50-m-high, 20ofrictionless slope. A strong headwind exerts a horizontal force of 200N on him as he skies. Use work and energy to find Sam鈥檚 speed at the bottom.

A pendulum is formed from a small ball of mass m on a string of length L. AsFIGURE CP10.69 shows, a peg is heighth=L3 above the pendulum鈥檚 lowest point. From what minimum angle u must the pendulum be released in order for the ball to go over the top of the peg without the string going slack?

FIGUREEX10.28shows the potential energy of a 500gparticle as it moves along the x-axis. Suppose the particle鈥檚 mechanical energy is 12J.

a. Where are the particle鈥檚 turning points?

b. What is the particle鈥檚 speed when it is at x=4.0m?

c. What is the particle鈥檚 maximum speed? At what position or positions does this occur?

d. Suppose the particle鈥檚 energy is lowered to 4.0J. Can the particle ever be at x=2.0m? Atx=4.0m?

A very slippery ice cube slides in a vertical plane around the inside of a smooth, 20-cm-diameter horizontal pipe. The ice cube鈥檚 speed at the bottom of the circle is 3.0m/s. What is the ice cube鈥檚 speed at the top?

A system has potential energy

Ux=x+sin2rad/mx

as a particle moves over the range0m鈮�x鈮�蟺m.

a. Where are the equilibrium positions in this range?

b. For each, is it a point of stable or unstable equilibrium?
See all solutions

Recommended explanations on Physics Textbooks

Engineering Physics

Read Explanation

Solid State Physics

Read Explanation

Oscillations

Read Explanation

Torque and Rotational Motion

Read Explanation

Kinematics Physics

Read Explanation

Linear Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.