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100mLof water at 15°Cis placed in the freezer compartment of a refrigerator with a coefficient of performance of 4.0. How much heat energy is exhausted into the room as the water is changed to ice at -15°C?

Short Answer

Expert verified

As a result, the heat emitted into the room is=5.3×104J.

Step by step solution

01

Step 1:The heat energy of the certain mass

The heat energy of a specific mass with a specific heat capacity that is subjected to a temperature difference is given as:

Q=mcΔT

Where m is the body's mass and C is its specific heat capacity and ΔTis the temperature difference.

02

The heat energy removed from the water

The mass of the water sample is :

m=100×10−3L10−3m31L1000kgm3

=0.100kg

The heat energy extracted from water is known as:

Q=(0.100kg)(4186J/kg⋅K)(15K)+(0.100kg)3.33×105J/kg

+(0.100kg)(2090J/kgâ‹…K)(15K)

=42714J

The performance metric is:

K=QCWin

As a result, the work input is

Wia=42714J4,0

The heat that is emitted into the room is:

Qu=Qc+Win

=42714J+10679J

=5.3×104J

As a result, the amount of heat emitted into the room is reduced 5.3×104J.

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