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A heat engine using a monatomic gas follows the cycle shown in FIGURE P21.58.

a. Find Ws,Q, and Δ·¡thfor each process in the cycle. Display your results in a table.

b. What is the thermal efficiency of this heat engine?

Short Answer

Expert verified

a. Table for process of cycle is .

b. The thermal efficiency is15%.

Step by step solution

01

Calculation for work done in first process (part a)

(a) .

The third process is adiabatic,

So the maximal pressure is,

p1V1γ=p3V3γ

⇒p1=V3V1γp3

So,

p1=61.67×100atm

=1993kPa

The first process is isobaric,

so,

T1=V2V1T2

=100K

The heat is,

Q=p2V2RT2Cp(600-100)m3

≈8300J

The work done is,

role="math" localid="1650269695241" W=1993×103J×500×10-6

≈1000J

02

Calculation for work in second process (part a) solution

a.

For second process the work done is null,

Q=p2V2RT2CpΔ°Õ

=p2V2RT2Cpp2-p3p2T2

=CpV2p2-p3R

So,

Q=12.5×6×10-4m3×1893×103J8.314Ω

≈2850J

The third point is,

T3=p3p2T2

role="math" localid="1650270106364" =100atm1993kPa×600m3

=30.1K

The heat is,

Q=p2V2RT2CvT3-T2

=-210J

03

Result for process in cycle part(a) solution

a.

04

Calculation for thermal efficiency (part b)

b.

From the table,

The total heat input is 5240J,

The work done is 790J.

The efficiency is,

η=790J5240J

=15%

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