91影视

Thermal efficiency is the ratio of net output to the energy input for a heat engine. Here cooling water keeps the cold source cool . The heat absorbed by water measures the heat dumped at cold source. Total heat input is sum of heat absorbed at cold source and heat output.

The Efficiency is,

$畏=\frac{P_e}{P_h}=\frac{P_e}{P_e+P_c}=1-\frac{P_c}{P_c+P_e}$

where $P_e$represents electric power output and $P_h$and $P_c$represent total input heating and cooling loss power, respectively.

When the temperature difference is $螖T$, the energy that mass $m$of water carries will be

$Q=cm螖T$

We acquire cooling power as a function of mass flow rate by dividing by time.

$P_c=c螖T\frac{螖m}{螖t}$

The mass can be calculated by multiplying the volume by the density, which gives us

$P_c=c螖T\frac{螖V}{蚁螖t}$

c is specific heat of water , $蚁$is density of water , $鈭�T,\frac{鈭�V}{鈭�t}$are temperature difference and volume rate of flow of water .

Substitute the values,

$畏=1-\frac{c螖T\frac{螖V}{蚁螖t}}{c螖T\frac{螖V}{蚁螖t}+P_e}$

We can calculate the efficiency numerically and then estimate it. We've got

$P_c=4180*(27-16)\frac{1*{10}^5}{1*{10}^3*3600}$

$=1277MW$

The Efficiency is,

localid="1649654360826" $$\begin{gathered} 畏=\frac{750}{1277+750} \\ =37\% \end{gathered}$$