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Chapter 24: Q. 4 (page 682)

The electric field is constant over each face of the cube shown in FIGURE EX24.4. Does the box contain positive charge, negative charge, or no charge? Explain.

Short Answer

Expert verified

The box has a negative charge.

Step by step solution

01

Step 1. Given Information

Over each face of the cube illustrated, the electric field is constant.

02

Step 2. Is there a positive charge, a negative charge, or no charge in the box?

According to Gauss's law 鈭�E鈫�路dA鈫�=Q蔚0,

Here E is the electric field, A is the area, Q is the charge and 蔚0is a constant

Now apply Gauss's law, to get

Q蔚0=鈭�E鈫�路dA鈫�=(-15-20-15+20+15+10)A=-5A

So, let have chargeQ=5A蔚0<0

鈬�The box has negative charge

Gauss's law for electric flux is used to determine the charge of the box.

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Most popular questions from this chapter

FIGURE EX24.17shows three charges. Draw these charges on your paper four times. Then draw two-dimensional cross sections of three-dimensional closed surfaces through which the electric flux is (a) 2q/系0, (b) q/系0, (c) 0,and (d) 5q/系0.

What is the net electric flux through the torus (i.e., doughnut shape) of FIGURE ?

A very long, uniformly charged cylinder has radius Rand linear charge density位. Find the cylinder's electric field strength (a) outside the cylinder, r鈮�R, and (b) inside the cylinder, r鈮�R. (c) Show that your answers to parts a and b match at the boundary, r=R

A 3.0-cm-diameter circle lies in the xz-plane in a region where the electric field isE鈫�=(1500i^+1500j^-1500k^)N/C. What is the electric flux through the circle?

A 2.0cm脳3.0cmrectangle lies in the xy-plane. What is the magnitude of the electric flux through the rectangle if

a. E鈫�=(100i^-200k^)N/C?

b. E鈫�=(100i^-200j^)N/C?
See all solutions

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