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Chapter 14: Q. 8 (page 383)

Blocks a, b, and c in FIGURE Q14.7 have the same density. Rank in order, from largest to smallest, the sizes of the buoyant forces Fa , Fb , and Fc on a, b, and c. Explain

Short Answer

Expert verified

The buoyant force is in order as: Fa =Fc >Fb

Step by step solution

01

Given information

The figure given with 3 objects with same density is submerged in liquid.

02

Explanation

Buoyant force acting on a mass floating in a liquid depends on density or object, submerged volume of object and gravity.

F= Vs 蟻g 鈥︹�︹�︹�︹�︹�︹��..(1)

Where

F = buoyant force

Vs = submerged volume

蟻 = density of liquid

g = gravity

We know that the density of the blocks are same so volume of block will be

V = Mass / Density

We have Ma =Mc =50g and Mb =40 g

So

Va =Vc >Vb ......................(2)

From the equation (1) we understand that Buoyant force depends on the Volume submerged if density of liquid is same.

Therefore from equation(1) and (2) we can conclude that

Fa =Fc >Fb.

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Most popular questions from this chapter

An object has density 蟻.
a. Suppose each of the object鈥檚 three dimensions is increased by a factor of 2 without changing the material of which the object is made. Will the density change? If so, by what factor? Explain.
b. Suppose each of the object鈥檚 three dimensions is increased by a factor of 2 without changing the object鈥檚 mass. Will the density change? If so, by what factor? Explain.

FIGURE Q14.4 shows two rectangular tanks, A and B, full of water. They have equal depths and equal thicknesses (the dimension into the page) but different widths.

a. Compare the forces the water exerts on the bottoms of the tanks. Is FA larger than, smaller than, or equal to FB? Explain.
b. Compare the forces the water exerts on the sides of the tanks. Is FA larger than, smaller than, or equal to FB? Explain.

What does the top pressure gauge read in FIGUREEX14.30?

A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30psi, but it's been a while since you've checked. You can't find a tire gauge in the car, but you do find the owner's manual and a ruler. Fortunately, you've just finished taking physics, so you tell your friend, "I don't know, but I can figure it out." From the owner's manual you find that the car's mass is1500kg. It seems reasonable to assume that each tire supports one-fourth of the weight. With the ruler you find that the tires are 15cm wide and the flattened segment of the tire in contact with the road is 13cm long. What answer-in psi-will you give your friend?

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