/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 37 聽A 20聽cm脳20聽cm聽square loop ... [FREE SOLUTION] | 91影视

91影视

Find study content
Learning Materials

Discover learning materials by subject, university or textbook.

Explanations

Textbooks
All Subjects

Anthropology

Archaeology

Architecture

Art and Design

Bengali

Biology

Business Studies

Greek

Chemistry

Chinese

Combined Science

Computer Science

Economics

Engineering

English

English Literature

Environmental Science

French

Geography

German

History

Hospitality and Tourism

Human Geography

Italian

Japanese

Law

Macroeconomics

Marketing

Math

Media Studies

Medicine

Microeconomics

Music

Nursing

Nutrition and Food Science

Physics

Polish

Politics

Psychology

Religious Studies

Sociology

Spanish

Sports Sciences

Translation

All Subjects

Biology

Business Studies

Chemistry

Combined Science

Computer Science

Economics

English

Environmental Science

Geography

History

Math

Physics

Psychology

Sociology
Features
Features

Discover all of these amazing features with a free account.

Flashcards

91影视 AI

Notes

Study Plans

Study Sets
What鈥檚 new?

Flashcards
Study your flashcards with three learning modes.

Study Sets
All of your learning materials stored in one place.

Notes
Create and edit notes or documents.

Study Plans
Organise your studies and prepare for exams.
91影视
Discover

All the hacks around your studies and career - in one place.

Find a degree

Magazine
Featured

Magazine
Trusted advice for anyone who wants to ace their studies & career.

The largest student job board with the most exciting opportunities.

Verified student deals from top brands.

Discover our mobile app to take your studies anywhere.

Learning Materials

Features

Discover

Chapter 30: Q. 37 (page 871)

A $20 cm 脳 20 cm$ square loop has a resistance of $0.10 惟$ . A CALC magnetic field perpendicular to the loop is $B = 4 t - 2 t^{2}$ , where $B$ is in Tesla and $t$ is in seconds. What is the current in the loop at $t = 0.0 s, t = 1.0 s$ ,and $t = 2.0 s ?$

Short Answer

Expert verified

Current in the loop at $I_{0 s}$ is $1.6 A$ .

Current in the loop at $I_{1 s}$ is $0 A$ .

Current in the loop at $I_{2 s}$ is $- 1.6 A$ .

Step by step solution

01

Formula for electric flux inside the loop

The magnetic field is expressed in terms of time in the form

$B = 4 t - 2 t^{2}$

The loop's current state is,

$I_{induced} = \frac{蔚}{R}$

$蔚 = |\frac{{诲桅}_{m}}{dt}|$

The electric flow as a function of area is,

$桅_{m} = NBA$

So,

$蔚 = NA \frac{d (BA)}{dt} = NA \frac{dB}{dt}$

02

Calculation for current in the loop att=0.0 s

Current that has been induced is,

$I_{induced} = (\frac{NA}{R}) \frac{dB}{dt}$

$= (\frac{NA}{R}) \frac{d}{dt} (4 t - 2 t^{2})$

$= (\frac{NA}{R}) (4 - 4 t)$

The area of the loop is calculated using

$A = 0.20 m 脳 0.20 m = 4 脳 10^{- 2} m^{2}$

At $t = 0.0 s$ :

Induced current is,

$I_{0 s} = (\frac{NA}{R}) (4 - 4 t)$

$= (\frac{(1) (4 脳 10^{- 2} m^{2})}{0.10 惟}) (4 - 4 (0 s))$

$= 1.6 A$

03

Calculation for current in the loop at t=1.0 s and t=2.0 s

At $t = 1.0 s$ :

Induced current is,

$I_{1 s} = (\frac{NA}{R}) (4 - 4 t)$

$= (\frac{(1) (4 脳 10^{- 2} m^{2})}{0.10 惟}) (4 - 4 (1 s))$

$= 0 A$

At $t = 2.0 s$ :

Induced current is,

$I_{2 s} = (\frac{NA}{R}) (4 - 4 t)$

$= (\frac{(1) (4 脳 10^{- 2} m^{2})}{0.10 惟}) (4 - 4 (2 s))$

$- 1.6 A$ $= (\frac{(1) (4 脳 10^{- 2} m^{2})}{0.10 惟}) (4 - 4 (1 s))$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

11. a. Can you tell which of the inductors in FIGURE Q30.11 has the larger current through it? If so, which one? Explain.

b. Can you tell through which inductor the current is changing more rapidly? If so, which one? Explain.

c. If the current enters the inductor from the bottom, can you tell if the current is increasing, decreasing, or staying the same? If so, which? Explain.

FIGURE Q30.11

FIGURE EX30.14 shows a 10-cm-diameter loop in three different magnetic fields. The loop's resistance is For each, what are the size and direction of the induced current

The 10-cm-wide, zero-resistance slide wire shown in FIGURE is pushed toward the $2.0 鈩�$ resistor at a steady speed of $0.50 m / s$ . The magnetic field strength is $0.50 T$ .

a. How big is the pushing force?

b. How much power does the pushing force supply to the wire?

c. What are the direction and magnitude of the induced current?

d. How much power is dissipated in the resistor?

The switch in FIGURE $EX 30.36$ has been open for a long time. It is closed at $t = 0 s$ .

a. What is the current through the battery immediately after the switch is closed $?$

b. What is the current through the battery after the switch has been closed a long time $?$

A rectangular metal loop with $0.050$ resistance is placed next to one wire of the RC circuit shown in $F I G U R E P 30.52$ . The capacitor is charged to $2 V$ with the polarity shown, then the switch is closed at $t = 0 s$ .

a. What is the direction of current in the loop for $t > 0 s$ ?

b. What is the current in the loop at $t = 5.0 渭 s$ ? Assume that

only the circuit wire next to the loop is close enough to produce a significant magnetic field.

See all solutions

Recommended explanations on Physics Textbooks

Work Energy and Power

Read Explanation

Mechanics and Materials

Read Explanation

Fundamentals of Physics

Read Explanation

Thermodynamics

Read Explanation

Fields in Physics

Read Explanation

Kinematics Physics

Read Explanation

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.