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Chapter 31: Q. 12 (page 901)

What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 10V/m ?

Short Answer

Expert verified

The magnetic field amplitude of an electromagnetic wave is3.33脳10-8T.

Step by step solution

01

Step 1: 

As it stand's,

E=10V/m

c=3脳108m/s

Electric field amplitude,

E=c路B

B-Magnitude field of amplitude.

localid="1648801389365" c-In a vacuum, the speed of light

02

Calculation of magnetic field amplitude

Electric field amplitude is,

E=c路B

from the formula,

both to be divided byc,

Ec=c路Bc

B=Ec

B=10V/m3脳108m/s

B=3.33脳10-8T

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Most popular questions from this chapter

The electric field of an electromagnetic wave in a vacuum is Ey=(20.0V/m)cos6.28脳108x-蝇迟, where is inlocalid="1648922287898" mandlocalid="1648922295234" tis in s. What are the wave's (a) wavelength, (b) frequency, and (c) magnetic field amplitude?

A rocket zooms past the earth at v=2.0脳106m/s. Scientists on the rocket have created the electric and mag-netic fields shown in FIGURE EX31.5. What are the fields measured by an earthbound scientist?

a. Show that uEand uB, the energy densities of the electric and magnetic fields, are equal to each other in an electromagnetic wave. In other words, show that the wave鈥檚 energy is divided equally between the electric field and the magnetic field.

b. What is the total energy density in an electromagnetic wave of intensity 1000W/m2?

A radio antenna broadcasts a1.0MHzradio wave with 25kWof power. Assume that the radiation is emitted uniformly in all directions.

a. What is the wave鈥檚 intensity 30 km from the antenna?

b. What is the electric field amplitude at this distance?

A wire with conductivity s carries current I. The current is increasing at the rate dI/dt.

a. Show that there is a displacement current in the wire equal to (鈭�o/蟽)(dI/dt)

b. Evaluate the displacement current for a copper wire in which the current is increasing at 1.0脳106A/s.
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