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The electric field at a point in space is $\stackrel{鈫�}{E}=(400\hat{i}+100\hat{j})\mathrm{N}/\mathrm{C}$

If a proton or electron is placed in space, the magnitude of the proton's acceleration and electron's acceleration is needed.

$protonmass=1.67262192脳{10}^{-27}kg$

$electronmass=9.10938脳{10}^{-31}kg$

The charge of the electron: $e=鈭�1.6脳{10}^{鈭�19}\mathrm{C}$

The charge of the proton:$p=1.6脳{10}^{-19}C$

The magnitude of the electric force (F) experienced by the proton is computed as:

$\begin{array}{r}F=\left|Ep\right|\\ =\left|(400\hat{i}+100\hat{j})\frac{\mathrm{N}}{\mathrm{C}}脳\left(1.6脳{10}^{鈭�19}\mathrm{C}\right)\right|\\ =(6.4\hat{i}+1.6\hat{j})脳{10}^{鈭�17}\mathbf{N}\end{array}$

The magnitude of the electric force (F) experienced by the electron is computed as:

$\begin{array}{r}F=Ee\\ =(400\hat{i}+100\hat{j})\frac{\mathrm{N}}{\mathrm{C}}脳\left(-1.6脳{10}^{鈭�19}\mathrm{C}\right)\\ =-(6.4\hat{i}+1.6\hat{j})脳{10}^{鈭�17}\mathbf{N}\end{array}$

The magnitude of the acceleration of the proton at that point is calculated as: $a_p=\frac{F_{net}}{m_p}$

The net force of the proton is calculated as $F_{net}=\sqrt{({(6.4脳{10}^{-17})}^2+{(1.6脳{10}^{-17})}^2)}=6.59脳{10}^{-17}N$

Plugging the above values in the above equation, we get proton's acceleration as:

$a_p=\frac{6.59脳{10}^{-17}}{1.7脳{10}^{-27}}=4脳{10}^{10}m/s^2$

The magnitude of the acceleration of the electron at that point is calculated as: $a_e=\frac{F_{net}}{m_e}$

The net force of the electron is calculated as

$F_{net}=\sqrt{({(-6.4脳{10}^{-17})}^2+{(-1.6脳{10}^{-17})}^2)}=6.59脳{10}^{-17}N$

Plugging the above values in the above equation, we get electron's acceleration as:

$a_e=\frac{6.59脳{10}^{-17}}{9.1脳{10}^{-31}}=7.3脳{10}^{13}m/s^2$