91影视

(a).

When two charged particles are separated by a distance $\mathrm{r}$one of them has a charge ${\mathrm{q}}_1$while the other has a charge ${\mathrm{q}}_2$.

The two particles exert forces on each other, with the force decreasing as the distance between them grows and increasing as the size of the charges increases.

This force is described by Coulomb's law.

${\mathrm{F}}_{\mathrm{C}}={\mathrm{F}}_{1\text{on}2}={\mathrm{F}}_{2\text{on}1}=\frac{{\mathrm{Kq}}_1{\mathrm{q}}_2}{{\mathrm{r}}^2}....1$

Where $\mathrm{K}$is the electrostatic constant, which is calculated as $9脳{10}^9{\mathrm{Nm}}^2/{\mathrm{C}}^2$.$9脳{10}^9{\mathrm{Nm}}^2/{\mathrm{C}}^2$

The proton has a charge of localid="1649086707721" $1.6脳{10}^{-19}\mathrm{C}$.

Substitute all values in equationlocalid="1649086712739" $1$

we obtain,

localid="1649086719377" ${\mathrm{F}}_{\mathrm{C}}=\frac{\mathrm{Kqe}}{{\mathrm{r}}^2}$

localid="1649086727135" $=\frac{\left(9.0脳{10}^9\mathrm{N}路{\mathrm{m}}^2/{\mathrm{C}}^2\right)\left(-15脳{10}^{-9}\mathrm{C}\right)\left(+1.6脳{10}^{-19}\mathrm{C}\right)}{(0.01\mathrm{m}{)}^2}$

localid="1649086733037" $=-2.16脳{10}^{-13}\mathrm{N}$

(a).

According to Newton's law, acceleration is inversely proportional to the mass of the object and directly proportional to the applied force.

${\mathrm{a}}_{\mathrm{p}}=\frac{{\mathrm{F}}_{\mathrm{C}}}{{\mathrm{m}}_{\mathrm{p}}}$

Where ${\mathrm{m}}_{\mathrm{p}}$is the proton's mass .

And${\mathrm{a}}_{\mathrm{p}}$is its acceleration.

Substitute all values,

$\left|{\mathrm{a}}_{\mathrm{p}}\right|=\left|\frac{{\mathrm{F}}_{\mathrm{C}}}{{\mathrm{m}}_{\mathrm{p}}}\right|$

$=\left|\frac{-2.16脳{10}^{-13}\mathrm{N}}{1.67脳{10}^{-27}\mathrm{kg}}\right|$

$=1.3脳{10}^{14}\mathrm{m}/{\mathrm{s}}^2$

The proton speeds up as it approaches the charge.

Force,

${\mathrm{F}}_{\mathrm{C}}=\frac{\mathrm{Kq}(-\mathrm{e})}{{\mathrm{r}}^2}$

$=\frac{\left(9.0脳{10}^9\mathrm{N}路{\mathrm{m}}^2/{\mathrm{C}}^2\right)\left(-15脳{10}^{-9}\mathrm{C}\right)\left(-1.6脳{10}^{-19}\mathrm{C}\right)}{(0.01\mathrm{m}{)}^2}$

$=2.16脳{10}^{-13}\mathrm{N}$

$\left|{\mathrm{a}}_{\mathrm{e}}\right|=\left|\frac{{\mathrm{F}}_{\mathrm{C}}}{{\mathrm{m}}_{\mathrm{e}}}\right|$

$=\left|\frac{2.16脳{10}^{-13}\mathrm{N}}{9.1脳{10}^{-31}\mathrm{kg}}\right|$

$=2.4脳{10}^{17}\mathrm{m}/{\mathrm{s}}^2$

The electron speeds up as it moves away from the charge.