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Chapter 6: Q.38 (page 156)

A 5.0 Kg object initially at rest at the origin is subjected to the time-varying force shown below. What is the object鈥檚 velocity at t=6sec.?

Short Answer

Expert verified

The objects velocity is 4 m/s.

Step by step solution

01

Given information

Mass of object at rest m=5.0kg

time t=6s

02

Explanation

We know that the expression for velocity is given by

V=at(I)where,V=velocitya=accelerationt=time

and According to Newton's second law,

F=maSo,a=Fm(II)

where,

f= force, m= mass, a= acceleration

Substituting (II)in (I)we get the formula needed to find the velocity

i.e.

V=Fm脳t(III)

The value F脳tcan be calculated from the given graph triangular area.

(i.e.,) The area of triangle=F脳t=12脳4脳10=20Ns

Now by Substituting the values in the equation (III), we get

V=205kgV=4m/s

The object's velocity is4m/s

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