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The pulling force transferred axially by a string, cable, chain, or similar item, or by each end of a rod, truss member, or similar three-dimensional object is known as tension.

Newton's first law of motion states that an item remains at rest or in uniform motion until it is acted with by a net external force.

The quantity of force exerted on an object is equal to the product of its mass and the acceleration generated, according to Newton's second equation of motion.

$F=ma$

In this scenario, the item is a box that has been put on frictionless ice and is being pushed horizontally by a rope. The rope's tension is the same as the net force pressing on the box.

$T=F=ma$

Box mass$\left(m\right)$= $50kg$,

rest velocity $v_x=0m/s$,

acceleration $a_x=0m/s^2$

$$\begin{gathered} T=50脳0 \\ T=0N \end{gathered}$$

Hence, when the box is at rest, the tension in the rope is$0N$.

In this scenario, the item is a box that has been put on frictionless ice and is being pushed horizontally by a rope. The rope's tension is the same as the net force pressing on the box.

$T=F=ma$

Box mass $\left(m\right)=50kg$,

uniform velocity $v_x=5m/s$,

acceleration $a_x=0m/s^2$.

$$\begin{gathered} T=50脳0 \\ T=0N \end{gathered}$$

Hence, when the box moves at uniform velocity, the tension in the rope is$0N$.

In this scenario, the item is a box that has been put on frictionless ice and is being pushed horizontally by a rope. The rope's tension is the same as the net force pressing on the box.

$T=F=ma$

Box mass $\left(m\right)=50kg$,

velocity $v_x=5m/s$,

acceleration $a_x=5m/s^2$.

$$\begin{gathered} T=50脳5 \\ T=250N \end{gathered}$$

Hence, when the box is accelerated, the tension in the rope is$250N$.