/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.28 A rubber-wheeled 50聽kg cart rol... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 6: Q.28 (page 155)

A rubber-wheeled 50kg cart rolls down a 15掳 concrete incline. What is the cart鈥檚 acceleration if rolling friction is

(a) neglected and

(b) included?

Short Answer

Expert verified

a. When the rolling friction in neglected a=2.54m/s2

b. When the rolling friction is includeda=2.35m/s2

Step by step solution

01

Content Introduction

Acceleration, charge at which speed modifications with time, in phrases of each velocity and course. A factor or an item transferring in a immediately line is extended if it hastens or slows down. Motion on a circle is extended even though the velocity is constant, due to the fact the course is usually changing.

02

Explanation (Part a)

The force identification diagram shows:

m=50kgis the mass, sin胃=15掳

localid="1648483374914" FGsin(胃)=Fneta=gsin15鈭�a=(9.8m/s2脳0.259)a=2.54m/s2

03

Explanation (Part b)

The rolling friction try to oppose the motion of the rubber wheel as it acts opposite to direction of motion. The force identification diagram depicts

FGsin胃-fr=Fnetfr=渭rn=渭rmgcos胃mgsin胃-渭rmgcos15掳=maa=(9.8m/s2脳0.259)-(0.02脳9.8m/s2脳0.96)=2.35m/s2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 1500 kg car skids to a halt on a wet road where 渭k=0.50. How fast was the car traveling if it leaves role="math" localid="1648126746388" 65m-long skid marks?

You're driving along at25m/swith your aunt's valuable antiques in the back of your pickup truck when suddenly you see a giant hole in the road 55 ahead of you. Fortunately, your foot is right beside the brake and your reaction time is zero!

a. Can you stop the truck before it falls into the hole?

b. If your answer to part a is yes, can you stop without the antiques sliding and being damaged? Their coefficients of friction are 渭s=0.60and渭k=0.30.

Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a 鈥渃rumple zone鈥� in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. By contrast, an unrestrained occupant keeps moving forward with no loss of speed (Newton鈥檚 first law!) until hitting the dashboard or windshield. These are unyielding surfaces, and the unfortunate occupant then decelerates over a distance of only about 5 mm.

a. A 60 kg person is in a head-on collision. The car鈥檚 speed at impact is 15 m/s. Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.

b. Estimate the net force that ultimately stops the person if he or she is not restrained by a seat belt or air bag.

A person with compromised pinch strength in his fingers can exert a force of only6.0Nto either side of a pinched object, such as the book shown in FIGURE P6.58. What is the heaviest book he can hold vertically before it slips out of his fingers? The coefficient of static friction between his fingers and the book cover is 0.80.

FIGURE P6.58

Compressed air is used to fire a 50 g ball vertically upward from a 1.0 m-tall tube. The air exerts an upward force of 2N on the ball as long as it is in the tube. How high does the ball go above the top of the tube?
See all solutions

Recommended explanations on Physics Textbooks

Thermodynamics

Read Explanation

Work Energy and Power

Read Explanation

Quantum Physics

Read Explanation

Electromagnetism

Read Explanation

Torque and Rotational Motion

Read Explanation

Electrostatics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.