91Ó°ÊÓ

The pulling force transferred axially by a string, cable, chain, or similar item, or by each end of a rod, truss member, or similar three-dimensional object is known as tension.

Newton's first law of motion states that an item remains at rest or in uniform motion until it is acted with by a net external force.

The quantity of force exerted on an object is equal to the product of its mass and the acceleration generated, according to Newton's second equation of motion.

$F=ma$

In this scenario, the item is a box that is suspended vertically by a rope. The free body diagram of the box is shown below.

$T=mg+m{a}_y$

Mass of box $\left(m\right)=50kg$,

Acceleration due to gravity $\left(g\right)=9.8m/s^2$,

rest velocity $v_y=0m/s$,

acceleration $a_y=0m/s^2$.

$T=m\left(g+a_y\right)$

$$\begin{gathered} T=50\left(9.8+0\right) \\ T=490N \end{gathered}$$

Hence, rope's tension value when the box is at rest is$490N$.

Mass of box $\left(m\right)=50kg$,

Acceleration due to gravity $\left(g\right)=9.8m/s^2$,

steady velocity $v_y=5m/s$,

acceleration $a_y=0m/s^2$.

Substituting values in equation,

$T=m\left(g+a_y\right)$

$$\begin{gathered} T=50\left(9.8+0\right) \\ T=490N \end{gathered}$$

Hence, rope's tension value when the box is moving with uniform velocity is$490N$.

Mass of box $\left(m\right)=50kg$,

Acceleration due to gravity $\left(g\right)=9.8m/s^2$,

velocity $v_y=5m/s$,

acceleration $a_y=5m/s^2$.

Substituting values in equation,

$T=m\left(g+a_y\right)$

$$\begin{gathered} T=50\left(9.8+5\right) \\ T=740N \end{gathered}$$

Hence, rope's tension value when the box is speeding up is$740N$.

Mass of box $\left(m\right)=50kg$,

Acceleration due to gravity $\left(g\right)=9.8m/s^2$,

velocity $v_y=5m/s$,

acceleration $a_y=-5m/s^2$.

Substituting values in equation,

$T=m\left(g+a_y\right)$

$$\begin{gathered} T=50\left(9.8-5\right) \\ T=240N \end{gathered}$$

Hence, rope's tension value when the box is speeding down is$240N$.