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Chapter 6: Q. 35 (page 155)

A 75kgskydiver can be modeled as a rectangular 鈥渂ox鈥� with dimensions 20cm*40cm*180cm.What is his terminal speed if he falls feet first? Use 0.8for the drag coefficient.

Short Answer

Expert verified

The terminal speed if he falls feet first is136.72m/sec.

Step by step solution

01

Given information.

Mass(m)=75kg,dimensions of the box shaped body =20cm*40cm*180cm,drag coefficient(C)=0.8.

02

Calculation

The formula for terminal velocity is given by:

v=2mg蚁ac.

here,

m=mass of the body

g=gravitational acceleration

蚁=density of air

a= Projected area

c = Drag Constant

The density of air islocalid="1648476929997" 1.23kg/m3.

Projected area :

(a)=20*40.=800cm2.=0.08m2.

03

Continuation of calculation

Putting the values we get,

v=2*(75kg)*(9.81m/s2)(1.23kg/m3)*(0.08m2)*(0.8).v=18692.8354m2/s2.v=136.72m/sec.

Therefore, the terminal velocity is136.72m/sec.

04

Final answer

The terminal speed if he falls feet first is136.72m/sec.

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