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The mean time between collisions in iron is 4.2×10-15s. What electron current is driven through a 1.8mmdiameter iron wire by a role="math" localid="1648885652366" 0.065V/melectric field ?

Short Answer

Expert verified

The amount of electron current is driven through a 1.8mmdiameter iron wire by a0.065V/melectric field islocalid="1648885800944" 1.04×1019.

Step by step solution

01

Given Information 

Meantime collision=4.2×10-15s

Iron wire diameter =1.8mm

Electric field=0.065V/m

02

Explanation

The electron current can be found as

ie=neAvd

Substitute the area of the cross-section for a circle, finding

ie=Ï€nevdD24.

Find the drift speed,

The expression for the electron intensity as

ie=πneeτD24m·E.

Substituting the values,

localid="1648885927955" ie=π×8.5×1028e×1.6×10-19c×4.2×10-15s×0.00182mm4×9.1×10-31kg×0.065V/m

Simplify the expression,

localid="1648885951677" =1.04×1019.

03

Final Answer

Hence the amount of electron current is driven through a 1.8mmdiameter iron wire by a 0.065V/melectric field is1.04×1019.

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