91Ó°ÊÓ

we have given that

A low-pass RC filter has a crossover frequency f_c =200 Hz

we have to find $f_c$ if resistance R is doubled

as we know in low- pass R C filter,

$f_c=\frac{1}{2\mathrm{Ï€}RC}$

according to given question

$f_c=\frac{1}{2\mathrm{Ï€}RC}=200$Hz

if resistance R is doubled

${\left(f_c\right)}^{\text{'}}=\frac{1}{2\mathrm{Ï€}\left(2R\right)C}=\frac{f_c}{2}=\frac{200}{2}=100$Hz

we have given that

A low-pass RC filter has a crossover frequency f_c=200 Hz

we have to find $f_c$if capacitance C is doubled

as we know in low- pass R C filter,

$f_c=\frac{1}{2\mathrm{Ï€}RC}$

according to given question

$f_c=\frac{1}{2\mathrm{Ï€}RC}=200$Hz

if capacitance C is doubled

${\left(f_c\right)}^{\text{'}}=\frac{1}{2\mathrm{Ï€}R\left(2C\right)}=\frac{f_c}{2}=\frac{200}{2}=100$Hz

we have given that

A low-pass RC filter has a crossover frequency f_c=200 Hz

we have to find $f_c$ if peak voltage E₀ is doubled

as we know in low- pass R C filter,

$f_c=\frac{1}{2\mathrm{Ï€}RC}$

according to given question

$f_c=\frac{1}{2\mathrm{Ï€}RC}=200$Hz

if peak emf E₀ is doubled there will be no change therefore,

$f_c=200$Hz