/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q9CQ By considering its constituents,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

By considering its constituents, determine the dimensions (e.g. length, distance over lime. etc.) of the denominator in equation(9−26). Why is the result sensible?

Short Answer

Expert verified

It follows that the denominator must be dimensionless so that the average energy also has units of energy

Step by step solution

01

Step 1:Equation (26)

Equation (26) writes:

∫N(E)D(E)dE

WhereNis the occupation number or simply the number of particles in a particular energy state,D(E)is the density of states anddEis the energy range.

02

Step 2:

In the above equation,N is dimensionless, D(E)has units of 1 /energy anddE has units of energy. Using dimensional analysis, equation (26) must therefore be dimensionless.

03

denominator must be dimensionless

This result is sensible because equation is one of the recipes to calculate the average energyE¯ Since the equation for average energy has numerator with units of energy, it follows that the denominator must be dimensionless so that the average energy also has units of energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The electrons’ contribution to the heat capacity of a metal is small and goes to 0as T→0. We might try to calculate it via the total internal energy, localid="1660131882505" U=∫EN(E)D(E)dE, but it is one of those integrals impossible to do in closed form, and localid="1660131274621" N(E)FDis the culprit. Still, we can explain why the heat capacity should go to zero and obtain a rough value.

(a) Starting withN(E)FDexpressed as in equation (34), show that the slope N(E)FDdEatE=EFis-1(4kBT).

(b) Based on part (a), the accompanying figure is a good approximation to N(E)FDwhen Tis small. In a normal gas, such as air, whenTis raised a little, all molecules, on average, gain a little energy, proportional to kBT. Thus, the internal energy Uincreases linearly with T, and the heat capacity, ∂U∂T, is roughly constant. Argue on the basis of the figure that in this fermion gas, as the temperature increases from 0to a small value T, while some particles gain energy of roughly kBT, not all do, and the number doing so is also roughly proportional to localid="1660131824460" T. What effect does this have on the heat capacity?

(c)Viewing the total energy increase as simply ∆U= (number of particles whose energy increases) (energy change per particle) and assuming the density of states is simply a constant Dover the entire range of particle energies, show that the heat capacity under these lowest-temperature conditions should be proportional to kBREFT. (Trying to be more precise is not really worthwhile, for the proportionality constant is subject to several corrections from effects we ignore).

At high temperature, the average energy of a classical one-dimensional oscillator is kBT, and for an atom in a monatomic ideal gas. it is 12kBT. Explain the difference. using the equipartition theorem.

Somehow you have a two-dimensional solid, a sheet of atoms in a square lattice, each atom linked to its four closest neighbors by four springs oriented along the two perpendicular axes. (a) What would you expect the molar heat capacity to be at very low temperatures and at very high temperatures? (b) What quantity would determine, roughly, the line between low and high?

  1. Using the Maxwell speed distribution, determine the most probable speed of a particle of mass min a gas at temperature T
  2. How does this compare with vrms ? Explain.

Show that. using equation(9−36), density of states(9−38)follows fromlocalid="1658380849671" (9−37)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.