/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q58E Show that. using equation聽(9鈭... [FREE SOLUTION] | 91影视

91影视

Show that. using equation(936), density of states(938)follows fromlocalid="1658380849671" (937)

Short Answer

Expert verified

The expression for density states ism32L3232E12 .

Step by step solution

01

Formula used 

The expression for density of energy state is given by,

D(E)=DifferentialnumberofstatesinrangedEdE

The expression for radial distance from origin is given by,

n=2mL2E22

02

Expression for density of energy state

The expression for density of energy state is calculated as,

D(E)=DifferentialnumberofstatesinrangedEdE=184n2dndE=184(2mL2E22)2ddE(2mL2E22)=(2)(2mL2E22)(L2)2mE

On further solving,

D(E)=L3232m3E24E=L323m3E2=m32L3232E12

Therefore, the expression for density states is .m32L3232E12

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The diagram shows two systems that may exchange both thermal and mechanical energy via a movable, heat-conducting partition. Because both Eand Vmay change. We consider the entropy of each system to be a function of both:S(E,V). Considering the exchange of thermal energy only, we argued in Section 9.2 that was reasonable to define1TasSE. In the more general case, PTis also defined as something.

a) Why should pressure come into play, and to what mightPTbe equated.

b) Given this relationship, show thatdS=dQT(Remember the first law of thermodynamics.)

Discusses the energy balance in a white dwarf. The tendency to contract due to gravitational attraction is balanced by a kind of incompressibility of the electrons due to the exclusion principle.

(a) Matter contains protons and neutrons, which are also fanions. Why do the electrons become a hindrance to compression before the protons and neutrons do?

(b) Stars several times our Sun's mass has sufficient gravitational potential energy to collapse further than a white dwarf; they can force essentially all their matter to become neutrons (formed when electrons and protons combine). When they cool off, an energy balance is reached like that in the white dwarf but with the neutrons filling the role of the incompressible fermions. The result is a neutron star. Repeat the process of Exercise 89. but assume a body consisting solely of neutrons. Show that the equilibrium radius is given by

R=322G(322mn8M)1/3

(c) Show that the radius of a neutron star whose mass is twice that of our Sun is only about10km .

Derivation of equation(940): Our model for calculatingEis equation (9-26), whose denominator is the total number of particlesNand whose numerator is the total energy of the system, which we here callUtotal. State with the denominator:

N=0N(E)(E)dE

Insert the quantum gas density of states and an expression for the distribution. usingto distinguish the Bose-Einstein from the Fermi-Dirac. Then change variables:E=y2, and factorBe+r2/kUTout of the denominator. In the integrand will be a factor

(11Bey2/kBT)1

Using,(l)11 a sum of two integrals results, each of Gaussian form. The integral thus becomes two terms in powers of1/B. Repeat the process. but instead find an expression forUtotalin terms of1/B, using

U|ntal=0EN(E)D(E)dE

Divide your expression forUtotalby that forN. both in terms of1/B. Now1/Bcan safely be eliminated by using the lowest-order expression forNin terms of1/B.

Exercise 67 calculates the minimum total energy in a system of spin fermions and is applicable to conduction electrons in a metal. The average particle energy is the total energy divided by the number of particlesN .Show that the average particle energy Eof a conduction electron at low temperature(T=0) is(3/5)EF . This form is convenient, being rather simple, and it can easily he put in terms of N,Vandm via equation .

Not surprisingly. in a collection of oscillators, as in other thermodynamic systems, raising the temperature causes particles' energies to increase. Why shouldn鈥檛 point be reached where there are more panicles in some high energy state than in a lower energy. state? (The fundamental idea, not a formula that might arise from it. is the object.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.