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Chapter 19: Q57P (page 799)

Consider a copper wire with a cross-sectional area of 1 mm2 (similar to your connecting wires ) and carrying 0.3 A of current, which is about what you get in a circuit with a thick-filament bulb and two batteries in series. Calculate the strength of the very small electric field required to drive this current through the wire.

Short Answer

Expert verified

The strength of the very small electric field required to drive this current through the wire is 5脳10-3V/m.

Step by step solution

01

Given data

The data can be listed as,

  • The cross-sectional area of copper wire is, A=1mm2=1脳10-6m2.
  • Current is, I=0.3A.
02

Concept

If a current flows in the circuit, it is influenced by many factors, such as the length of the wire, the cross-sectional area of the wire, and the applied voltage on the wire.

03

Determination of the required electric field

The wire is made of copper metal only.

The required electric field can be determined using the formula as,

E=蚁IA

Here 蚁is the resistivity of the copper wire whose value is 16.78脳10-9惟路m.

Substitute the values in the above expression, and we get,

E=16.78脳10-9惟路m0.3A1脳10-6m2=5.03脳10-3惟路m-1路A~5脳10-3V/m

Thus, the strength of the very small electric field required to drive this current through the wire is 5脳10-3V/m.

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Most popular questions from this chapter

Should an ammeter have a low or high resistance? Why? Should a voltmeter have a low or high resistance? Why?

The capacitor in Figure 19.65 is initially charged, then the circuit is connected. Which graph in Figure 19.66 best describes the current through the bulb as a function of time?

A circuit consists of two batteries (with negligible resistance), six ohmic resistors and connecting wires that have negligible resistance. The resistance R1is 10惟, R2 is 20惟, R3 is 30惟, R4is 12惟, R5is 15惟 and R6 is 20惟. Unknown currents I1,I2 ,I3 ,I4 , I5 and I6 have their directions marked on the circuit diagram in figure 19.87.

(a) Write down a set of equations that could be solved for the six unknown currents. Make sure you can explain how to you got these equations. (b) When a correct set of equations is solved the currents are as follows (to the nearest miiampeares) I1=0.4394A, I2=0.3312A, I3=0.0065A, I4=0.1082A, I5=0.3247Aand I6=0.4329A. Check your equations by substituting in these numbers. (c) Suppose that you connect the negative lead of a voltmeter to location C. What does the voltmeter read, including both magnitude and sign? (d) What does the power output of the 5 V battery? (e) Resistor is made of a very thin metal wire that is 3 mm long, with a diameter of 0.1 mm. What is the electric field inside the metal resistor.

The capacitor in Figure 19.67 is initially uncharged, then the circuit is connected. Which graph in Figure 19.66 best describes the absolute value of the charge on the left plate as a function of time?

Two resistor each with resistance of 4脳106惟 are connected in series to a 60 V power supply whose internal resistance is negligible. You connect the voltmeter across one of these resistors and this voltmeter has an internal resistance of 1脳106惟. What is the reading on the voltmeter?
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