/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q2Q The velocityv(t) of a particle ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The velocityv(t)of a particle undergoing SHM is graphed in Fig. 15-20b. Is the particle momentarily stationary, headed toward+xm, or headed toward-xmat (a) point A on the graph and (b) point B? Is the particle at-xm, at+xm, at 0, between and 0, or between 0 andlocalid="1657280889199" +xmwhen its velocity is represented by (c) point A and (d) point B? Is the speed of the particle increasing or decreasing at (e) point A and (f) point B?

Short Answer

Expert verified
  1. The particle is headed towards -xm at point A.
  2. The particle is headed towards +xmat point B.
  3. Position of particle is between-xm when velocity is represented by point A.
  4. Position of particle is between-xm when velocity is represented by point B.
  5. Speed of particle is decreasing at point A.
  6. Speed of particle is increasing at point B.

Step by step solution

01

The given data 

From the problem the figure 15-20(b) is the graph of is given.

02

Understanding the concept of the SHM

Observing the graph we can find the direction of motion of the particle in the instant. From the absolute value of the velocity, we can find the speed of the particle whether it is increasing or decreasing.

03

Calculation of the behavior of the particle at point A on the graph

a)

From the graph the maximum velocity of the particle is at point 2 which is at left mean position and point 4 which is at right mean position. At the extreme position, the velocity of particle is 0.

From the graph, the particle is moving from point 2 to point 3 that means the particle is moving from left mean position to left extreme position so the heading of particle at point A is towards -xm.

04

Calculation of the behavior of the particle at point B on the graph

b)

From the graph we can see that particle is moving from point 3 to point 4 that is from left extreme position to right mean position, so the heading of particle at point B is towards +xm.

05

Calculation of the position of the particle when velocity is represented by point A

c)

Fromthegraph the particle is moving from point 2 to point 3 that meantheparticle is moving from left mean position to left extreme position so the position of the particle is between0and-xm when velocity is represented by point A.

Therefore, the position of the particle is betweenrole="math" localid="1657281422664" -xmand0 when velocity is represented by point A.

06

Calculation of the position of the particle when velocity is represented by point B

d)

From the graph, we can see that particle is moving from point 3 to point 4 that is from left mean position to right extreme position, so the position of the particle is between0and-xm when the velocity is represented by point B.

Therefore, the position of the particle is betweenrole="math" localid="1657281563133" -xmand0 when velocity is represented by point B.

07

Calculation of the behavior of the speed of the particle at point A

e)

From the graph speed of particle is decreasing at point A because absolute value of velocity is decreasing at point A.

Therefore, the speed of particle is decreasing at point A.

08

Calculation of the behavior of the speed of the particle at point B

f)

From the graph the speed of the particle is increasing because the absolute value of velocity is increasing towards+Vmax.

Therefore, the speed of the particle is increasing at point B.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An engineer has an odd-shaped 10kgobject and needs to find its rotational inertia about an axis through its center of mass. The object is supported on a wire stretched along the desired axis. The wire has a torsion constant, k=0.50N.m. If this torsion pendulum oscillates through50cycles in50s, what is the rotational inertia of the object?

A loudspeaker diaphragm is oscillating in simple harmonic motion with a frequency of440Hzand a maximum displacement of0.75mm.

  1. What is the angular frequency?
  2. What is the maximum speed?
  3. What is the magnitude of the maximum acceleration?

A spider can tell when its web has captured, say, a fly because the fly’s thrashing causes the web threads to oscillate. A spider can even determine the size of the fly by the frequency of the oscillations. Assume that a fly oscillates on the capture thread on which it is caught like a block on a spring. What is the ratio of oscillation frequency for a fly with mass mto a fly with mass2.5m?

A particle executes linear SHM with frequency 0.25Hz about the point x=0. Att=0, it has displacement x=0.37cm and zero velocity. For the motion, determine the (a) period, (b) angular frequency, (c) amplitude, (d) displacement x(t), (e) velocity v(t), (f) maximum speed, (g) magnitude of the maximum acceleration, (h) displacement at t=3.0s, and (i) speed att=30s.

Question: An oscillator consists of a block attached to a spring (k = 400 N/m). At some time t, the position (measured from the system’s equilibrium location), velocity, and acceleration of the block are, x =0.100 m,v = 13.6 m and a = 123 m/s2. Calculate (a) the frequency of oscillation,(b) the mass of the block, and (c) the amplitude of the motion.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.