/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.48 Table A practice(a) z<-2.46.(... [FREE SOLUTION] | 91影视

91影视

Table A practice

(a) z<-2.46.

(b) z>2.46

(c) 0.89<z<2.46

(d) -2.95<z<-1.27

Short Answer

Expert verified

a).Area(z<-2.46)=0.0069.

b). Area (z>2.46)=0.0069.

c). The area between z=0.89z=2.46is 0.9931-0.8133=0.1798.

d). The area between z=-2.95&z=-1.27is 0.1020-0.0016=[0.1004]

Step by step solution

01

Part (a) Step 1: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

02

Part (a) Step 2: Explanation

The table of areas beneath the standard normal curve is called the below standard normal probabilities table. The area under the curve to the left of each number zis the table entry.

03

Part (a) Step 3: Explanation

The area to the left of z=-2.46is 0.0069.

04

Part (b) Step 1: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

05

Part (b) Step 2: Explanation

The area to the left of z=2.46is 0.991. Thus, the area to the right of z=2.46is 1-0.9931=0.0069.

06

Part (c) Step 3: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

07

Part (c) Step 2: Explanation

From the Standard Normal probabilities table, the area to the left of -=0,89is 0.8133and the area to the left of z=2.46is 0.9931. The area between z=2.46and z=0.89is the area to the left of 2.46minus the area to the left of 0.89.

Therefore, the area between z=0.89&z=2.46is 0.9931-0.8133=0.1798.

08

Part (d) Step 1: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

09

Part (d) Step 2: Explanation

From the Standard Normal probabilities table, the area to the left of z=-1.27is 0.1020and the area to the left of z=-2.95is 0.0016. The area between z=-2.95and z=-1.27is the area to the left of -1.27minus the area to the left of -2.95.

Therefore, the area between z=-2.95&z=-1.27is 0.1020-0.0016=0.1004.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

SAT versus ACT Eleanor scores 680 on the SAT Mathematics test. The distribution of SAT scores is

symmetric and single-peaked, with mean 500and standard deviation 100. Gerald takes the American College Testing (ACT) Mathematics test and scores 27. ACT scores also follow a symmetric, singlepeaked distribution鈥攂ut with mean 18 and standard deviation 6. Find the standardized scores for both students. Assuming that both tests measure the same kind of ability, who has the higher score?

Gas it up! (1.3) Interested in a sporty car? Worried that it might use too much gas? The Environmental Protection Agency lists most such vehicles in its 鈥渢wo-seater鈥 or 鈥渕inicompact鈥 categories. The figure shows boxplots for both city and highway gas mileages for our two groups of cars. Write a few sentences comparing these distributions.

Brent is a member of the school鈥檚 basketball team. The mean height of the players on the team is 76 inches. Brent鈥檚 height translates to a z-score of 0.85 in the team鈥檚 height distribution. What is the standard deviation of the team members鈥 heights?

Use Table A to 铿乶d the proportion of observations from the standard Normal distribution that satis铿乪s each of the following statements. In each case, sketch a standard Normal curve and shade the area under the curve that is the answer to the question. Use your calculator or the Normal Curve applet to check your answers.

More Table A practice

(a) zis between 鈭1.33and 1.65

(b) zis between 0.50and1.79

Now suppose that you convert the class鈥檚 heights to z-scores. What would be the shape, center, and spread of this distribution? Explain.
See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.