91影视

To find that the given$t$ statistic is one-sample, paired, or two-sample.

Two sets of birds are compare to the test.
The first group consists of $7$pairings, while the second group consists of $6$pairs.
Because the sample sizes differ, paired data cannot be included in the samples.
As a result, the two-sample is the$t$ statistic

To explain the value of $t$ leads to the quoted conclusion.

Let, the statistic $t=-1.05$

Find the null and alternative hypotheses:
$H_o:{渭}_1={渭}_2$
$H_a:{渭}_1鈮�{渭}_2$
Find the degree of freedom as:
$df=\min \left(n_1-1,n_2-1\right)$

$=\min (7-1,6-1)$

$=5$

Using table $B$, calculate the $p$-value as:

$p-\text{value}=2脳P(t>鈭�1.05鈭�)$

$=0.342$

Note that, $p$-value is greater than the significance level.

When the P-value is less than or equal to the significance level, then the null hypothesis will be rejected:
$P>0.05鈬�\text{Fail to reject}{H}_0$

The null hypothesis is not rejected.

Hence, there is insufficient evidence to support the quoted conclusion.