/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 The eating habits of 12 bats wer... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The eating habits of 12 bats were examined in the article "Foraging Behavior of the Indian False Vampire Bat" (Biotropica [1991] \(63-67\) ). These bats consume insects and frogs. For these 12 bats, the mean time to consume a frog was \(\bar{x}=21.9\) minutes. Suppose that the standard deviation was \(s=7.7\) minutes. Construct and interprer a \(90 \%\) confidence interval for the mean suppertime of a vampire bat whose meal consists of a frog. What assumptions must be reasonable for the one-sample \(t\) interval to be appropriate?

Short Answer

Expert verified
The 90 % confidence interval for the mean meal time for a bat eating a frog is between 14.97 and 28.83 minutes. The assumptions for this inference are: the population is normally distributed, the samples are independent and it is a simple random sample.

Step by step solution

01

Identify parameters

The first step is to pinpoint the key parameters - sample size (n), sample mean (\(\bar{x}\)) and sample standard deviation (s). In this case, n = 12, \(\bar{x}\) = 21.9 minutes, and s = 7.7 minutes.
02

Determine critical value

A 90% confidence interval implies a significance level (α) of 0.10. We need the critical value (t*) that corresponds to this confidence level. Since the degrees of freedom is \(n-1\), we will use 11 degrees of freedom. Looking at the t-distribution table, for α/2 = 0.05 and 11 degrees of freedom, we get t* = 1.796.
03

Calculate Confidence Interval

To calculate confidence interval, we use the formula \[Confidence Interval = \bar{x} \pm t* \cdot \frac{s}{\sqrt{n}}\] Substituting the values, the confidence interval becomes \[21.9 \pm 1.796 \cdot \frac{7.7}{\sqrt{12}}\]. This yields the interval: \(14.97 to 28.83\) minutes.
04

Assumptions for one-sample t-interval

For a one-sample t interval to be suitable, these assumptions need to be made: \n 1. The population from which the samples are taken is normally distributed. \n 2. The samples are independent of each other. \n 3. The sample taken is random, and each member of the population has an equal chance of being in the sample.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics
Statistics is the field of study that involves the collection, analysis, interpretation, presentation, and organization of data. When we talk about statistics in the context of confidence intervals, we're referring to inferential statistics, which allows us to make predictions or inferences about a population based on a sample of data.

For instance, in the exercise, the data from 12 bats is used to make an inference about the average supper time for the vampire bat population. It's crucial in statistics to understand that we use samples because it's often impractical or impossible to study an entire population. Therefore, statistical methods like the construction of confidence intervals help us to estimate population parameters, like mean supper time, with a known level of confidence.
One-sample t-test
The one-sample t-test is a statistical test used to determine whether there is a significant difference between the sample mean and a known or hypothesized value of the mean in the population. This test is particularly useful when we do not know the population standard deviation, and the sample size is relatively small, typically less than 30.

In the bat study, we are using the sample mean time it takes for bats to consume a frog to estimate the population mean time, and the one-sample t-test would help to ascertain if our sample is representative of the population. It's an assumption that the population from which the sample is drawn follows a normal distribution, especially important when dealing with small sample sizes.
Sample mean
The sample mean, denoted as \(\bar{x}\), is simply the average of all the measurements in a sample. It serves as the best point estimate of the population mean (\(\mu\)).

To calculate the sample mean, one would add up all the observed values and divide by the number of observations. In our given exercise, the mean time for 12 bats to eat their meal was 21.9 minutes. This value gives us a central point around which the data is spread. However, the sample mean is just part of the story, as it doesn't tell us how much individual times might vary, which is why we also look at measures of spread like the standard deviation.
Standard deviation
Standard deviation, symbolized as s, is a measure that is used to quantify the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean, while a high standard deviation indicates that the values are spread out over a wider range.

It is calculated as the square root of the variance, which is the average of the squared differences from the mean. In the bat example, a standard deviation of 7.7 minutes suggests there is a relatively modest spread in the times it takes different bats to consume a frog. The standard deviation is a critical component in the calculation of a confidence interval because it impacts the margin of error and, consequently, the width of the interval.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How much money do people spend on graduation gifts? In \(2007,\) the National Retail Federation (www.nff.com) surveyed 2815 consumers who reported that they bought one or more graduation gifts that year. The sample was selected in a way designed to produce a sample representative of adult Americans who purchased graduation gifts in 2007. For this sample, the mean amount spent per gift was \(\$ 55.05\). Suppose that the sample standard deviation was \(\$ 20 .\) Construct and interpret a \(98 \%\) confidence interval for the mean amount of money spent per graduation gift in 2007 .

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked how many months had passed since their last visit to a dentist. Their responses were as follows: \(\begin{array}{llll}6 & 17 & 11 & 22\end{array}\) 29 Assuming that these five students can be considered a random sample of all students participating in the free checkup program, construct a \(95 \%\) confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program.

Acrylic bone cement is sometimes used in hip and knee replacements to fix an artificial joint in place. The force required to break an acrylic bone cement bond was measured for six specimens under specified conditions, and the resulting mean and standard deviation were 306.09 Newtons and 41.97 Newtons, respectively. Assuming that it is reasonable to believe that breaking force under these conditions has a distribution that is approximately normal, estimate the mean breaking force for acrylic bone cement under the specified conditions using a \(95 \%\) confidence interval.

Tongue Piercing May Speed Tooth Loss. Researchers Say" is the headline of an article that appeared in the San Luis Obispo Tribune (June 5,2002 ). The article describes a study of 52 young adults with pierced tongues. The rescarchers found receding gums, which can lead to tooth loss, in 18 of the participants. Construct a \(95 \%\) confidence interval for the proportion of young adults with pierced tongues who have receding gums. What assumptions must be made for use of the \(z\) confidence interval to be appropriate?

Consumption of fast food is a topic of interest to researchers in the field of nutrition. The article "Effects of Fast-Food Consumption on Energy Intake and Diet. Quality Among Children" reported that 1720 of those in a random sample of 6212 U.S. children indicated that on a typical day, they ate fast food. Estimate \(p\), the proportion of children in the United States who eat fast food on a tvpical dav.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.