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The interval from -2.33 to 1.75 captures an area of .95 under the \(z\) curve. This implies that another large-sample \(95 \%\) confidence interval for \(\mu\) has lower limit \(\bar{x}-2.33 \frac{\sigma}{\sqrt{n}}\) and upper limit \(\bar{x}+1.75 \frac{\sigma}{\sqrt{n}},\) Would you recommend using this \(95 \%\) interval over the \(95 \%\) interval \(\bar{x} \pm 1.96 \frac{\sigma}{\sqrt{n}}\) discussed in the text? Explain. (Hint: Look at the width of each interval.)

Short Answer

Expert verified
No, one would not recommend using the confidence interval \(\bar{x}-2.33 \frac{\sigma}{\sqrt{n}}\) to \(\bar{x}+1.75 \frac{\sigma}{\sqrt{n}}\) because the interval is wider than the standard 95% confidence interval, \(\bar{x} \pm 1.96 \frac{\sigma}{\sqrt{n}}\), therefore it is less precise.

Step by step solution

01

Determine Width of Confidence Interval \(\bar{x}\pm 2.33 \frac{\sigma}{\sqrt{n}}\)

The width of this interval is the difference between the upper and the lower limit, i.e., \(1.75- (-2.33) = 1.75 + 2.33 = 4.08\)
02

Determine Width of Confidence Interval \(\bar{x}\pm 1.96 \frac{\sigma}{\sqrt{n}}\)

This is the standard 95% confidence interval, and its width is \(1.96 - (-1.96) = 1.96 + 1.96 = 3.92\) using the same method as in step 1.
03

Compare the Widths

Upon comparing 4.08 (width of the first interval) and 3.92 (width of the standard interval), it can be seen that the confidence interval \(\bar{x}\pm 1.96 \frac{\sigma}{\sqrt{n}}\) is narrower as compared to \(\bar{x}\pm 2.33 \frac{\sigma}{\sqrt{n}}\). Therefore, this interval is preferred because it offers the same level of confidence (95%) while providing a narrower interval for the population mean, \(\mu\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-distribution
The Z-distribution is an essential concept in statistics, especially when discussing confidence intervals and hypothesis testing. It denotes the standard normal distribution, which has a mean of 0 and a standard deviation of 1. In the context of confidence intervals, it helps us determine how much our data deviates from the mean.

When dealing with large sample sizes (usually n > 30), the Central Limit Theorem tells us that the sample mean will approximately follow a normal distribution, even if the original population data is not normally distributed. This is why the Z-distribution is useful when constructing confidence intervals for large samples.

The Z-score, which corresponds to the Z-distribution, is the number of standard deviations a data point is from the mean. By using tables or statistical software, we can find Z-scores that correspond to specific confidence levels, such as 95%, allowing us to construct these confidence intervals.
  • The Z-distribution is symmetric around zero.
  • Confidence intervals using this distribution are great for estimating population parameters.
  • Z-distribution is particularly useful when population standard deviation is known.
Sample Mean
The sample mean, denoted as \( \bar{x} \), is the average of the sample data points. It is a crucial concept in statistics because it provides a single value that represents the center of the data set.

In confidence interval calculations, the sample mean serves as the best point estimate of the population mean \( \mu \). This means that it gives us the most likely value of the average of the entire population.

When constructing a confidence interval, we use the sample mean as the focal point. We then add and subtract a margin of error to find the interval range within which we expect the population mean to fall.
  • The sample mean is a way to summarize data with a single value.
  • It is sensitive to outliers, so consider this in data interpretation.
  • Sample size affects the reliability of the sample mean's approximation to the population mean.
Standard Deviation
Standard deviation is a measure of the spread of a set of values. It indicates how much the values in the dataset deviate from the mean. A small standard deviation implies that the values are closely clustered around the mean, while a large standard deviation shows that the values are more spread out.

In the context of confidence intervals, the standard deviation plays a vital role in determining the width of the interval. Specifically, it is part of the formula that calculates the margin of error, \( \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the standard deviation and \( n \) is the sample size. A smaller standard deviation or a larger sample size will generally result in a narrower confidence interval, which is more precise.
  • Standard deviation tells us about the variability of data.
  • It's used to calculate margin of error in confidence intervals.
  • Provides insight into the data's consistency or volatility.
Population Parameter Estimation
Population parameter estimation is the process of using sample data to make inferences about a larger population. In statistics, we're often interested in parameters like the population mean or population standard deviation. However, these parameters are seldom known accurately. Instead, they are estimated using sample statistics.

Confidence intervals are a common way to estimate population parameters. They provide a range of values within which we expect the population parameter to lie, with a certain degree of confidence, such as 95%.

This process involves using the Z-distribution, the sample mean, and standard deviation to calculate the confidence interval. It's crucial because it allows for conclusions about a population without needing to collect data from every individual within it.
  • Population parameter estimation helps make informed conclusions about a large group.
  • We rely on statistical methods to ensure these estimations are as accurate as possible.
  • Allows us to draw inferences even when only limited data is available.

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Most popular questions from this chapter

The Gallup Organization conducts an annual survey on crime. It was reported that \(25 \%\) of all households experienced some sort of crime during the past year. This estimate was based on a sample of 1002 randomly selected households. The report states, "One can say with \(95 \%\) confidence that the margin of sampling error is ±3 percentage points." Explain how this statement can be justified.

Tongue Piercing May Speed Tooth Loss. Researchers Say" is the headline of an article that appeared in the San Luis Obispo Tribune (June 5,2002 ). The article describes a study of 52 young adults with pierced tongues. The rescarchers found receding gums, which can lead to tooth loss, in 18 of the participants. Construct a \(95 \%\) confidence interval for the proportion of young adults with pierced tongues who have receding gums. What assumptions must be made for use of the \(z\) confidence interval to be appropriate?

One thousand randomly selected adult Americans participated in a survey conducted by the Assodated Press (June 2006 ). When asked "Do you think it is sometimes justified to lie or do you think lying is never justified?" \(52 \%\) responded that lying was never justified. When asked about lying to avoid hurting someone's feelings, 650 responded that this was often or sometimes okay. a. Construct a \(90 \%\) confidence interval for the proportion of adult Americans who think lying is never justified. b. Construct a \(90 \%\) confidence interval for the proportion of adult American who think that it is often or sometimes okay to lie to avoid hurting someone's feelings. c. Comment on the apparent inconsistency in the responses given by the individuals in this sample.

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked how many months had passed since their last visit to a dentist. Their responses were as follows: \(\begin{array}{llll}6 & 17 & 11 & 22\end{array}\) 29 Assuming that these five students can be considered a random sample of all students participating in the free checkup program, construct a \(95 \%\) confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program.

The paper "The Curious Promiscuity of Queen Honey Bees (Apis mellifera), Evolutionary and BehavIoral Mechanisms" (Annals of Zoology Fennic \(120011: 255-\) 265 ) describes a study of the mating behavior of queen honeybees. The following quote is from the paper: Queens flew for an average of \(24.2 \pm 9.21\) minutes on their mating flights, which is consistent with previous findings. On those flighrs, queens effectively mated with \(4.6 \pm 3.47\) males (mean \(\pm \mathrm{SD})\). a. The intervals reported in the quote from the paper were based on data from the mating flights of \(n=\) 30 queen honeybees. One of the two intervals reported is stated to be a confidence interval for a population mean. Which interval is this? Justify your choice. b. Use the given information to construct a \(95 \%\) confidence interval for the mean number of partners on a mating flight for queen honeybees. For purposes of this exercise, assume that it is reasonable to consider these 30 queen honeybees as representative of the population of queen honeybees.

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