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How much money do people spend on graduation gifts? In \(2007,\) the National Retail Federation (www.nff.com) surveyed 2815 consumers who reported that they bought one or more graduation gifts that year. The sample was selected in a way designed to produce a sample representative of adult Americans who purchased graduation gifts in 2007. For this sample, the mean amount spent per gift was \(\$ 55.05\). Suppose that the sample standard deviation was \(\$ 20 .\) Construct and interpret a \(98 \%\) confidence interval for the mean amount of money spent per graduation gift in 2007 .

Short Answer

Expert verified
The 98% confidence interval for the mean amount spent on graduation gifts in 2007 is calculated based on the given mean, standard deviation, and the Z value for a 98% confidence interval. The exact values of this interval can be determined by computing the margin of error and adding and subtracting it from the mean. Finally, we conclude that we are 98% confident that the true mean of the population falls within this calculated interval.

Step by step solution

01

Identify the given values

In the problem, the following values are given: \n 1. Sample Mean (\(\bar{x}\)): $55.05 \n 2. Sample Standard Deviation (s): $20 \n 3. Sample Size (n): 2815. Note: Since the sample size is greater than 30, we are justified in using a Z-distribution to calculate our confidence interval.
02

Find the appropriate Z-value

For a 98% confidence interval, the associated Z-value (which you can find in a standard Z-score table or by using an online calculator) is approximately 2.33.
03

Calculate the Margin of Error

Margin of Error (E) is calculated by the formula: E = Z * (s/√n) \n Plugging in the values from steps 1 and 2, we get: E = 2.33 * ($20/√2815). Compute this value to get the margin of error.
04

Construct the Confidence Interval

The confidence interval is calculated by taking the mean and adding and subtracting the margin of error. That is, (mean - E) to (mean + E). Calculate these values to get the final confidence interval.
05

Interpret the Confidence Interval

Interpreting the confidence interval in the context of this problem, we can say with 98% confidence that the true mean amount that all American adults spent on graduation gifts in 2007 falls within this interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, often denoted as \( \bar{x} \), plays a crucial role in statistical analysis. Imagine you want to know the average amount people typically spend on graduation gifts. Instead of asking everybody, because that would be impossible, you ask a smaller group - a sample. The sample mean is the average of this smaller group, and it represents the best guess of the overall population's mean.In the provided exercise, the sample mean was \( \\(55.05 \). This indicates that, based on the surveyed group, the average expenditure on graduation gifts in 2007 was approximately \( \\)55.05 \) per gift. It's a starting point for further analysis, especially when we need to make inferences about the entire population.
Standard Deviation
Standard deviation is a measure of how spread out the numbers in a data set are. It's like a ruler showing how much variation exists from the average, or mean. A low standard deviation means that most of the numbers are close to the average, while a high standard deviation indicates a wider spread.In the context of the exercise, the standard deviation was \( \\(20 \). This suggests that the amount spent on graduation gifts varied by about \( \\)20 \) from the average of \( \$55.05 \). When creating a confidence interval, a smaller standard deviation generally leads to a more precise interval, as the data points are closer to the mean.
Z-distribution
The Z-distribution, also known as the standard normal distribution, is a cornerstone of statistical analysis. It is a symmetrical bell-shaped curve that shows the distribution of data points in a normal dataset. This distribution becomes crucial when dealing with large sample sizes. For our exercise, since the sample size of 2815 is significantly large, we justify our use of the Z-distribution to calculate the confidence interval. The Z-distribution allows us to estimate the range in which the true population mean lies, when the population standard deviation is unknown but the sample size is suitably large. For a 98% confidence interval, the Z-value used is approximately 2.33, found using a standard Z-score table or calculator. This value tells us about the probability of the mean falling within a particular range.
Margin of Error
The margin of error is what gives us the wiggle room around our sample mean, making it possible to create a confident range for the true mean. It is essentially the little buffer that accounts for any sampling variability. The margin of error can be calculated using the formula: \[ E = Z \times \left( \frac{s}{\sqrt{n}} \right) \] where \( Z \) is the Z-value, \( s \) is the standard deviation, and \( n \) is the sample size.In our exercise on graduation gifts, the margin of error allows us to say that while the average spending was \( \$55.05 \), thanks to the margin of error, the true average spending could be a bit lower or higher. After performing the calculation using \( Z = 2.33 \), \( s = 20 \), and \( n = 2815 \), you gain this crucial information that helps define the confidence interval.

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