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The formula used to compure a confidence interval for the mean of a normal population when \(n\) is small is $$ \bar{x} \pm(t \text { critical value }) \frac{s}{\sqrt{n}} $$ What is the appropriate \(t\) critical value for each of the following confidence levels and sample sizes? a. \(95 \%\) confidence, \(n=17\) b. \(90 \%\) confidence, \(n=12\) c. \(99 \%\) confidence, \(n=24\) d. \(90 \%\) confidence, \(n=25\) e. \(90 \%\) confidence, \(n=13\) f. \(95 \%\) confidence, \(n=10\)

Short Answer

Expert verified
The appropriate t critical values for the given confidence levels and sample sizes are: a. 2.120 b. 1.796 c. 2.807 d. 1.711 e. 1.782 f. 2.262. These values may have slight variations based on the t-distribution table used.

Step by step solution

01

Prepare Inputs and Table for t critical values

Prepare the inputs as per the problem and use a standard t-distribution table to find critical values. You will look up the t critical values based on degrees of freedom (\(n-1\)) and the given confidence levels.
02

Computing t critical value for 95% confidence, n=17

First, calculate the degrees of freedom as \(17 - 1 = 16\). For 95% confidence, we look for the t value against 16 degrees of freedom in the t-distribution table. Normally, this value is 2.120.
03

Calculating t critical value for 90% confidence, n=12

The degrees of freedom are \(12 - 1 = 11\). For 90% confidence, the t value for 11 degrees of freedom in the t-distribution table is approximately 1.796.
04

Calculating t critical value for 99% confidence, n=24

Determine the degrees of freedom, which are \(24 - 1 = 23\). For a 99% confidence level, the t value for 23 degrees of freedom from the table is approximately 2.807.
05

Calculating t critical value for 90% confidence, n=25

Calculate the degrees of freedom as \(25 - 1 = 24\). The t value for 90% confidence and 24 degrees of freedom is approximately 1.711.
06

Calculating t critical value for 90% confidence, n=13

The degrees of freedom are \(13 - 1 = 12\). So the t value for 90% confidence level and 12 degrees of freedom is approximately 1.782.
07

Calculating t critical value for 95% confidence, n=10

Lastly, we calculate the degrees of freedom as \(10 - 1 = 9\). So the t value for 95% confidence level and 9 degrees of freedom is approximately 2.262.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values, derived from sample statistics, that is likely to contain the value of an unknown population parameter. For example, if you're looking at the average height of a group of people, the confidence interval provides a range that, with a certain degree of confidence, is expected to include the true average height of the entire population from which the sample is drawn.

The formula for a confidence interval for the mean, particularly when dealing with small sample sizes (generally less than 30), is given by \[ \bar{x} \pm(t \text{ critical value}) \frac{s}{\sqrt{n}}\] where \(\bar{x}\) is the sample mean, \(s\) is the sample standard deviation, \(n\) is the sample size, and the \(t\text{ critical value}\) corresponds to the desired confidence level and degrees of freedom. The \(t\text{ critical value}\) is obtained from the t-distribution table. The plus-minus sign indicates that the interval extends equally in both directions from the sample mean.
Degrees of Freedom
Degrees of freedom, often denoted as df, are a concept in statistics used to define the number of independent values or quantities that can be assigned to a statistical distribution. In the context of the t-distribution and t critical values, the degrees of freedom are typically calculated as the sample size minus one, denoted as \(n-1\).

The degrees of freedom affect the shape of the t-distribution and, consequently, the critical values needed to calculate the confidence intervals. As the degrees of freedom increase, the t-distribution increasingly resembles the normal distribution. When using the t-distribution, one must look up the critical value corresponding to the calculated degrees of freedom and the desired confidence level.
T-Distribution Table
The t-distribution table is used to determine the critical values for the t-distribution based on the degrees of freedom and the desired confidence level – typically 90%, 95%, or 99%. The critical value is key in constructing confidence intervals and is found at the intersection of the column representing the confidence level and the row corresponding to the degrees of freedom.

In the exercise, for instance, to find the 95% confidence t critical value for a sample size of 17, you subtract 1 from 17 to find the degrees of freedom (which would be 16) and then look at the row for 16 df in relation to the 95% confidence column in the t-distribution table.
Sample Size
Sample size, denoted \(n\), is the number of observations or data points collected in a statistical sample. It is a crucial component to many statistical formulas and concepts, including the calculation of confidence intervals. The sample size directly affects the degrees of freedom (\(df = n - 1\)) and, thus, the t critical value and the width of the confidence interval: the larger the sample size, the narrower the confidence interval and the more precise the estimate.

It's worth noting that larger sample sizes yield critical values closer to the critical values used for a normal distribution, as the t-distribution becomes less tailed and more 'normal' with increased degrees of freedom.
Statistical Inference
Statistical inference involves drawing conclusions about a population's characteristics based on a random sample from that population. Confidence intervals are one of the tools used in statistical inference, providing a range for an unknown parameter that is supported by the collected data with a certain level of confidence. This allows for informed decision-making in the face of uncertainty.

Understanding and calculating the t critical value for constructing confidence intervals is part of the process of statistical inference, enabling researchers and statisticians to make predictions or decisions regarding the broader population from their sample data.

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Most popular questions from this chapter

If a hurricane was headed your way, would you evacuate? The headline of a press release issued lanuary 21, 2009 by the survey research company International Communications Research (icrsurvey,com )states, "Thirtyone Percent of People on High-Risk Coast Will Refuse Evacuation Order, Survey of Hurricane Preparedness Finds." This headline was based on a survey of 5046 adults who live within 20 miles of the coast in high hurricane risk counties of eight southern stares. In selecting the sample, care was taken to ensure that the sample would be representative of the population of coastal residents in these states. Use this information to estimate the proportion of coastal residents who would evacuate using a \(98 \%\) confidence interval. Write a few sentences interpreting the interval and the confidence level associated with the interval.

In spite of the potential safety hazards, some people would like to have an Internet connection in their car. A preliminary survey of adult Americans has estimated this proportion to be somewhere around . 30 (USA Today. May 1, 2009\()\). a. Use the given preliminary estimate to determine the sample size required to estimate the proportion of adult Americans who would like an Internet connection in their car to within .02 with \(95 \%\) confidence. b. The formula for determining sample size given in this section corresponds to a confidence level of \(95 \%\). How would you modify this formula if a \(99 \%\) confidence level was desired? c. Use the given preliminary estimate to determine the sample size required to estimate the proportion of adult Americans who would like an Internet connection in their car to within .02 with \(99 \%\) confidence.

How much money do people spend on graduation gifts? In \(2007,\) the National Retail Federation (www.nff.com) surveyed 2815 consumers who reported that they bought one or more graduation gifts that year. The sample was selected in a way designed to produce a sample representative of adult Americans who purchased graduation gifts in 2007. For this sample, the mean amount spent per gift was \(\$ 55.05\). Suppose that the sample standard deviation was \(\$ 20 .\) Construct and interpret a \(98 \%\) confidence interval for the mean amount of money spent per graduation gift in 2007 .

In an AP-AOL sports poll (Associated Press, December 18,2005\(), 394\) of 1000 randomly selected U.S. adults indicared that they considered themselves to be baseball fans. Of the 394 baseball fans, 272 stated that they thought the designated hitter rule should either be expanded to both baseball leagues or eliminated. a. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults who consider themselves to be bascball fans. b. Construct a \(95 \%\) confidence interval for the proportion of those who consider themselves to be baseball fans who think the designated hitter rule should be expanded to both leagues or eliminated. c. Explain why the confidence intervals of Parts (a) and (b) are not the same width even though they both have a confidence level of \(95 \%\).

USA Today (October 14, 2002) reported that \(36 \%\) of adult drivers admit that they often or sometimes talk on a cell phone when driving. This estimate was based on data from a sample of 1004 adult drivers, and a bound on the error of estimation of \(3.1 \%\) was reported. Assuming a \(95 \%\) confidence level, do you agree with the reported bound on the error? Explain.

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