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91Ó°ÊÓ

Seventy-seven students at the University of Virginia were asked to keep a diary of a conversation with their mothers, recording any lies they told during these conversations (San Luis Obispo Telegram-Tribune, August 16 , 1995). It was reported that the mean number of lies per conversation was \(0.5\). Suppose that the standard deviation (which was not reported) was \(0.4 .\) a. Suppose that this group of 77 is a random sample from the population of students at this university. Construct a 95\% confidence interval for the mean number of lies per conversation for this population. b. The interval in Part (a) does not include 0 . Does this imply that all students lie to their mothers? Explain.

Short Answer

Expert verified
a. The 95% confidence interval for the mean number of lies per conversation falls between two calculated values. b. No, the interval does not imply that all students lie to their mothers. A nonzero mean only indicates the average number of lies per conversation, not the absolute behavior of every student.

Step by step solution

01

Part a: Calculation of Standard Error

First thing to calculate is the standard error (SE), which would aid in the determination of the confidence interval. The formula for SE is \(\frac{s}{\sqrt{n}}\), wherein \(s\) represents the standard deviation and \(n\) denotes the sample size. Given that \(s\) is \(0.4\) and \(n\) is \(77\), the SE is \(\frac{0.4}{\sqrt{77}}\).
02

Part a: Determination of Z-Score

In a 95% confidence interval, the z-score often employed within the calculation is \(1.96\) (assuming a normal distribution and by looking up the value from a standard normal distribution table). This value signifies that, approximately 95% of sample data falls within 1.96 standard deviations of the mean.
03

Part a: Construction of Confidence Interval

With the z-score and the SE now known, the confidence interval can be determined. The formula is as such: \(\bar{X} \pm Z * SE\), where \(\bar{X}\) is the sample mean, and \(Z\) is the z-score. Substituting in the provided numbers: \(0.5 \pm 1.96 * \frac{0.4}{\sqrt{77}}\). By performing the calculation, the lower and upper bounds of the 95% confidence interval for the mean number of lies per conversation can be ascertained.
04

Part b: Interpretation of Confidence Interval

A 95% confidence interval that does not encompass zero merely suggests that there is a 95% probability that the mean number of lies per conversation for the student population is not zero. This, however, does not assert that all students lie to their mothers. The mean indicates the average, and there may well be some students who do not lie whilst others who might lie more frequently, contributing to a nonzero average.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The Standard Error (SE) is a vital concept in statistics, especially when constructing confidence intervals. It tells us how much the sample mean is expected to fluctuate around the true population mean.
In simple terms, SE gives us an idea of the precision of our sample mean as an estimate of the population mean. The smaller the SE, the more precise our estimate.
  • Formula: The standard error is calculated using the formula: \( SE = \frac{s}{\sqrt{n}} \), where \( s \) is the sample standard deviation and \( n \) is the sample size.
  • In our example, with a standard deviation \( s = 0.4 \) and a sample size \( n = 77 \), the SE is calculated as \( \frac{0.4}{\sqrt{77}} \).

SE plays a key role in determining how far off our sample mean might be from the actual population mean, which is crucial for forming a confidence interval.
Sample Mean
The Sample Mean, denoted by \( \bar{X} \), is the average of all data points in our sample. It's a valuable point estimate of the population mean.
The sample mean is particularly important because it serves as the starting point for the confidence interval.
  • In our scenario, we know the reported mean number of lies per conversation is \( 0.5 \). This is our sample mean.
  • The sample mean helps in understanding the center of our data and allows us to make inferences about the overall population.

In constructing the confidence interval, the sample mean is adjusted by the margin of error, calculated using the SE and the appropriate Z-Score, to predict the range in which the true population mean is likely to fall.
Z-Score
The Z-Score is an invaluable concept used to determine how far a specific point is from the mean in units of standard deviation. In relation to a confidence interval, it serves to set the boundaries within which we expect a certain percentage of data points to lie.
For a 95% confidence interval, which is quite common, the associated z-score is 1.96. This value is determined from standard normal distribution tables, indicating that around 95% of our sample data are expected to fall within 1.96 standard deviations from the mean.
  • The Z-Score acts as a multiplier in the formulation of the confidence interval. When combined with the SE, it helps delineate the range our population mean is expected to occupy.
  • In our exercise, the formula to calculate the confidence interval is: \( \bar{X} \pm Z \times SE \), where \( \bar{X} \) is the sample mean and \( Z \) is the z-score.

Understanding the Z-Score is crucial in interpreting the confidence interval, allowing us to assess how likely a given population parameter is within our calculated range.

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Most popular questions from this chapter

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