/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Conducts an annual survey 6 of a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Conducts an annual survey 6 of all households expe the past year. This esti102 randomly selected adults. The report states, "One can say with \(95 \%\) confidence that the margin of sampling error is \(\pm 3\) percentage points." Explain how this statement can be justified.

Short Answer

Expert verified
The statement can be justified by saying that in repeated surveys under the same conditions, we would expect the true population value to lie within ±3% of the reported value in 95 out of 100 surveys.

Step by step solution

01

Understanding Confidence Intervals

In statistics, a confidence interval gives an estimated range of values which is likely to include an unknown population parameter. The confidence level is designated before examining the data. If the interval calculated includes the true value, it is said to 'cover' the parameter.
02

Calculating Confidence Interval

Imagine for a particular survey result, the reported percentage is \(p\% \). The 95% confidence interval for this percentage is understood to be \(p \pm 3 \% \). That is, we can be 95% confident that the true percentage, if the entire population were surveyed, would lie within 3 percentage points of the reported percentage. Remember that the width of the confidence interval gives us some idea about how uncertain we are about the unknown parameter (a wide interval suggests greater uncertainty; a small interval suggests greater confidence).
03

Understanding Margin of Sampling Error

The margin of error is the range of values below and above the sample statistic in a confidence interval. The range of the confidence interval is defined by the sample statistic plus the margin of error. The uncertainty is denoted by the confidence level, in this case it's 95%, which implies that if we conduct the survey 100 times, we would expect the proportion of the population to fall within these bounds 95 times.
04

Justification of the Statement

The statement 'One can say with 95% confidence that the margin of sampling error is ±3 percentage points' means that if this survey were repeated many times under the same conditions, 95 out of 100 times the results would vary by no more than ±3 percentage points of the reported percentage. This is a statement about the degree of reliability of the data given the size of the sample and the observed results, and shows that the result is statistically significant within the stated bounds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Sampling Error
Understanding the margin of sampling error is crucial when interpreting survey results. This term represents the extent to which the results obtained from a sample might differ from the true population parameter. For instance, when a survey estimates that 50% of voters prefer a candidate with a margin of sampling error of ±3%, this means the actual proportion in the entire population could reasonably be as low as 47% or as high as 53%.

The margin of sampling error depends on several factors, including the size of the sample and the variability of the population. Larger samples will generally have a smaller margin of error, reflecting a higher precision in the estimation of the population parameter. On the other hand, greater variability within the population usually leads to a larger margin of error. This is why a well-designed survey is crucial to minimize the margin of sampling error and to yield results that come closer to reflecting the true state of the population.
Confidence Level
The confidence level is a measure of the certainty or reliability associated with a statistical estimate. A 95% confidence level, as mentioned in the survey report, means we can be 95% certain that the interval computed from our sample statistic will contain the true population parameter. In other words, if we were to take 100 different samples and compute a confidence interval for each of them, we expect that 95 out of those 100 intervals will include the true value.

It's important to remember that the confidence level doesn't tell us the chance that a particular interval contains the population parameter, but rather how often the estimation method we're using will produce an interval that does so. The selection of the confidence level is subjective; a higher confidence level implies a wider interval, suggesting more certainty but less precision, and vice versa.
Population Parameter
A population parameter is a value that describes a certain characteristic of an entire population. In surveys and research, we often want to estimate parameters like the mean, proportion, or standard deviation of a population. Since surveying the whole population is usually not feasible, we sample a portion and then use those sample statistics to estimate the population parameter.

Parameters are fixed but often unknown quantities. It's the goal of statistical inference to estimate them with a degree of accuracy and confidence. By using a sample, we can compute statistics like the sample mean or sample proportion, and then construct a confidence interval around these estimates to understand the range within which the true population parameter likely falls.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In 1991, California imposed a "snack tax" (a sales tax on snack food) in an attempt to help balance the state budget. A proposed alternative tax was a \(12 \phi\) -per-pack increase in the cigarette tax. In a poll of 602 randomly selected California registered voters, 445 responded that they would have preferred the cigarette tax increase to the snack tax (Reno Gazette-Journal, August 26, 1991). Estimate the true proportion of California registered voters who preferred the cigarette tax increase; use a \(95 \%\) confidence interval.

Why is an unbiased statistic generally preferred over a biased statistic for estimating a population characteristic? Does unhiasedness alone onarantee that the estimate

Recent high-profile legal cases have many people reevaluating the jury system. Many believe that juries in criminal trials should be able to convict on less than a unanimous vote. To assess support for this idea, investigators asked each individual in a random sample of Californians whether they favored allowing conviction by a 10-2 verdict in criminal cases not involving the death penalty. The Associated Press (San Luis Obispo TelegramTribune, September 13,1995 ) reported that \(71 \%\) supported the \(10-2\) verdict. Suppose that the sample size for this survey was \(n=900\). Compute and interpret a \(99 \%\) confidence interval for the proportion of Californians who favor the \(10-2\) verdict.

Increases in worker injuries and disability claims have prompted renewed interest in workplace design and regulation. As one particular aspect of this, employees required to do regular lifting should not have to handle unsafe loads. The article "Anthropometric, Muscle Strength, and Spinal Mobility Characteristics as Predictors of the Rating of Acceptable Loads in Parcel Sorting" (Ergonomics [1992]: \(1033-1044\) ) reported on a study involving a random sample of \(n=18\) male postal workers. The sample mean rating of acceptable load attained with a work-simulating test was found to be \(\bar{x}=9.7 \mathrm{~kg}\). and the sample standard deviation was \(s=4.3 \mathrm{~kg}\). Suppose that in the population of all male postal workers, the distribution of rating of acceptable load can be modeled approximately using a normal distribution with mean value \(\mu\). Construct and interpret a \(95 \%\) confidence interval for \(\mu\).

The following data are the calories per half-cup serving for 16 popular chocolate ice cream brands reviewed by Consumer Reports (July 1999): \(\begin{array}{llllllll}270 & 150 & 170 & 140 & 160 & 160 & 160 & 290 \\ 190 & 190 & 160 & 170 & 150 & 110 & 180 & 170\end{array}\) Is it reasonable to use the \(t\) confidence interval to compute a confidence interval for \(\mu\), the true mean calories per half-cup serving of chocolate ice cream? Explain why or. why not.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.