/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 The eating habits of 12 bats wer... [FREE SOLUTION] | 91Ó°ÊÓ

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The eating habits of 12 bats were examined in the article "Foraging Behavior of the Indian False Vampire Bat" (Biotropica [1991]: \(63-67\) ). These bats consume insects and frogs. For these 12 bats, the mean time to consume a frog was \(\bar{x}=21.9\) min. Suppose that the standard deviation was \(s=7.7 \mathrm{~min}\). Construct and interpret a \(90 \%\) confidence interval for the mean suppertime of a vampire bat whose meal consists of a frog. What assumptions must be reasonable for the one-sample \(t\) interval to be appropriate?

Short Answer

Expert verified
The 90% confidence interval for the mean supper time of a vampire bat consuming a frog is from 17.9 minutes to 25.9 minutes. The assumptions for using the one-sample t interval here include randomness and representation of the sample, and normality of the population or large enough sample size.

Step by step solution

01

Identify Given Values

The mean time (\(\bar{x}\)) to consume a frog is given as 21.9 minutes, the standard deviation (s) is given as 7.7 minutes, and the number of bats (n) examined is 12.
02

Calculate Standard Error

The standard error is calculated using the formula, SE = \(s / \sqrt{n}\), where s is the standard deviation and n is the number of observations. Plugging in the given values we get, SE = \(7.7 / \sqrt{12}\) = 2.225.
03

Determine t-value

Since we want to construct a 90% confidence interval, and our degrees of freedom (df) is 11 (calculated as n - 1). We can look up for the t-value in the t-distribution table or use a calculator. The t-value for 90% confidence level and 11 degrees of freedom is approximately 1.796.
04

Calculate Confidence Interval

We calculate the lower and upper limit of the interval using the formula: \((\bar{x}) \pm t \times SE\). Doing the calculations, we get \(21.9 \pm 1.796 \times 2.225\), thus the 90% confidence interval is from \(17.9\) minutes to \(25.9\) minutes.
05

Interpret the Confidence Interval

The interpretation of the confidence interval is that we are 90% confident that the true mean time for a bat to consume a frog falls between 17.9 minutes and 25.9 minutes.
06

Discuss the assumptions

For the one-sample t-test to be appropriate, the following assumptions need to be met: 1) The sample is random and representative of the population 2) The distribution of the population is approximately normal, or if it's not, the sample size must be large enough (n>30).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval provides a range of values which is used to estimate the true parameter of a population. In this exercise, we're looking at a 90% confidence interval for the mean time it takes bats to consume a frog.
This means we are 90% certain that the true average time falls within this range. Confidence intervals are expressed by the formula: \(\bar{x}\pm t \times SE\). Here, \(\bar{x}\) represents the sample mean, \(t\) is the t-value from the t-distribution, and \(SE\) is the Standard Error.
Understanding the confidence interval allows scientists to make educated guesses about population parameters based on sample data. For the bats, a 90% confidence interval stretching from 17.9 to 25.9 minutes shows a "zone" where the true mean is likely to be.
t-distribution
The t-distribution is a critical concept when dealing with small sample sizes like the 12 bats here. This probability distribution helps us make inferences about the population mean when the sample size is small and the population standard deviation is unknown.
The t-distribution is similar to a normal distribution but tends to have thicker tails. This accounts for the greater variability found in smaller samples. The applicable t-value in this problem, obtained from a t-table, corresponds to the desired level of confidence and degrees of freedom. For our problem, degrees of freedom (df) is determined by \(n-1\), which is 11 because \(n = 12\).
In the end, using the t-distribution aids in obtaining a more accurate confidence interval compared to using a normal distribution.
Standard Error
The Standard Error (SE) is an essential statistic for understanding how sample means estimate population means. It measures the variability or "spread" of the sample mean within the population. A lower SE indicates a more accurate estimate of the population mean.
SE is calculated using the formula: \(s / \sqrt{n}\), where \(s\) is the sample standard deviation, and \(n\) is the sample size. For the bat example, an SE of 2.225 shows us how much the sample mean might deviate from the true population mean due to sample variability.
The smaller the SE, the more reliable your sample mean estimate will be, which is crucial when constructing a confidence interval.
One-Sample t-Test
The One-Sample t-Test is pivotal for determining if a sample mean significantly differs from a known population mean when dealing with small sample sizes.
In the bat study, it helps us infer the average frog consumption time from just the sampled bats. Using it, researchers can test hypotheses about the mean with more confidence despite the smaller sample size.
For this test to be appropriate, certain assumptions must be met:
  • The sample must be random and representative of the population.
  • The population distribution should ideally be normal.
  • If not normal and the sample size is smaller (like here, \(n=12\)), certain adjustments or considerations may be necessary.

This test is ideal when a precise population standard deviation is not available but a representative sample is.

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